greatest floating point number?

I know of LONG_MAX for intergers, but what is the identifer for the largest and smallest floats and which header file is it in ?

i can't remember the name of the constant, but the header file is called 'limits.h' and if you browse through it the answer should be easy to find.

float
32 bits
1.18x10^-38 < |X| < 3.40x10^38 Scientific (7-digit) precision)


double
64 bits
2.23x10^-308 < |X| < 1.79x10^308 Scientific (15-digit precision)


long double
80 bits
3.37x10^-4932 < |X| < 1.18x10^4932 Financial (18-digit precision)

>but the header file is called 'limits.h'
float.h, or cfloat for new C++ headers.

>float
>32 bits
>1.18x10^-38 < |X| < 3.40x10^38 Scientific (7-digit) precision)
The size of float, double, and long double are implementation-defined.

Code:

---

#include <iostream>
#include <cfloat>

int main()
{
  std::cout<< FLT_MAX <<'\n'<< DBL_MAX <<'\n'<< LDBL_MAX <<std::endl;
 
  return 0;
}

---

-Prelude

I know 32-bit flaoting number representation.
Are the double and long double the same?

I think prelude is right, sizes are implementation defined. The values I gave will be probable.

I guess C++ standard will only goes as far as:

sizeof(double) <= sizeof(long double)

The other words, they may be or may not be equal.

On my machine, FLT_MAX is the same as yours, Davros: 3.40282e+38.

DBL_MAX = 1.79769e+308 and LDBL_MAX = 1.18973e+4932, again, on my machine.

A long double is an eensy bit larger. :D

-Skipper

Code:

---

#undef max
#include <limits>

//To obtain the maximum values
std::numeric_limits<float>::max()
std::numeric_limits<double>::max()
std::numeric_limits<long double>::max()

---