argv and argc command line params

how do i accept command line parameters onto a program running under windows, i understand argv is the number of arguements but for eg - if i wanted to accept a 2 as a command line param and act on it - how do i do it.
tia

i thought argc held the number of arguments where argv held the arguments ??

Welcome back!!!!!

I'm assuming you mean a Win32 Program that uses WinMain???

If so, the third param of WinMain is a LPSTR which will give you the command line as a string ..

Also, you can use the GetCommandLine() API at any point to get this data......

You need some sort of way to tokenise the commandline - so look at strtok from the Std C Library

Quote:

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i thought argc held the number of arguments where argv held the arguments ??

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That is correct. Except that argc will contain number of args + 1, and argv[0] will contain the name of the program.

The data is in character format, so to extract a number, do:

int first_arg = atoi(argv[1]);

But always remember to check the count in argc, if it is 1, then nothing was entered into the command line, and the program should probably exit gracefully ;)

By the way, the naming convention is arbitrary, you could equally do:

int main(int count, char* array_of_commands[])

Code:

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#include <stdio.h>

int main(int argc, char *argv[])
{
    while (--argc)
        printf ("%s ", *++argv);
    return 0;
}


/* OR */

int main(int argc, char *argv[])
{
    int i;
    for (i = 1; i < argc; i++)
        puts(argv[i]);
    return 0;
}

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