how to assign value to structure array

Hi all, I'm having a little bit of trouble with my code about structures

I have decleared structure and I want to initialize array in single statement

Code:

---

#include<stdio.h>
#include<stdlib.h>

struct point
{
    int array[5];
};


int main()
{
    struct point svar;
    struct point spvar;
   
    svar.array[5] = {1, 2, 3, 4, 5};
       
    return 0;
}

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error

Code:

---

error: expected expression before '{' token
svar.array[5] = {1, 2, 3, 4, 5}

---

can anyone tell me what's the reason of error

You are setting the sixth element to a array.

Code:

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svar.array[5] = {1, 2, 3, 4, 5};

---

Try

Code:

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svar.array = {1, 2, 3, 4, 5};

---

My Bad.. Try this

Code:

---

#include <stdio.h>
#include <stdlib.h>

struct point
{
    int array[5];
};

int main(int argc, char ** argv) {
    struct point svar = {{1,2,3,4,5}};
    struct point spvar;
   
    return 0;
}

---

Quote:

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Originally Posted by G4143

You are setting the sixth element to a array.

Code:

---

svar.array[5] = {1, 2, 3, 4, 5};

---

Try

Code:

---

svar.array = {1, 2, 3, 4, 5};

---

---

I tried that but I am getting same error. I have GCC compiler

Unfortunately, you cannot assign to an array itself. However, you can initialise them, and in this case it means initialising the struct of which the array is a member:

Code:

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struct point svar = {1, 2, 3, 4, 5};

---

or if you want to consider that the struct may have more members:

Code:

---

struct point svar = {{1, 2, 3, 4, 5}};

---

Quote:

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Originally Posted by laserlight

if you want to consider that the struct may have more members:

Code:

---

struct point svar = {{1, 2, 3, 4, 5}};

---

---

Code:

---

#include<stdio.h>

#include<stdlib.h>


struct point
{
    int array[5];
};




int main()
{
  int i;
  struct point *spvar;
  struct point svar = {{1, 2, 3, 4, 5}};
 
  spvar = &svar;
 
  for ( i = 0; i < 5; i++)
  {
          printf( "%d ", *spvar );
          spvar++;
  }
 
    return 0;
}

---

when code run it gives output 1 6422296 4199048 0 4199157 and I was expecting 1, 2, 3, 4, 5

You have to understand C and pointers..

Code:

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struct point *spvar;

---

This pointer is not pointing at an integer, its pointing at a struct. Just for your benefit. Try taking the sizeof(int) and the sizeof(struct point).

Quote:

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Originally Posted by Dadu@

when code run it gives output 1 6422296 4199048 0 4199157 and I was expecting 1, 2, 3, 4, 5

---

spvar is a pointer to struct point. Therefore, *spvar is a struct point. So what you're doing here:

Code:

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printf( "%d ", *spvar );

---

is trying to print a struct point object as if it were an integer. It isn't. Your compiler should have warned you about that, and if it didn't, you need to compile at a high warning level and pay attention to warnings.

What you want to do is something like this:

Code:

---

#include<stdio.h>
#include<stdlib.h>


struct point
{
    int array[5];
};


int main(void)
{
    struct point svar = {{1, 2, 3, 4, 5}};

    for (size_t i = 0; i < 5; i++)
    {
        printf("%d ", svar.array[i]);
    }
    printf("\n");

    return 0;
}

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