how much memory structure take in code

I am confused with structure size

Code:

---

#include <stdio.h>
struct point
{
    int x;
    char y;
}s1;
   
int main()
{
    s1.x = 20;
    s1.y ='A';
   
 printf("s1.x= %d \n", s1.x);
 printf("s1.y= %c \n", s1.y);
 
 printf("Size of Structure : %d \n", sizeof(s1));
 
    return 0;
}

---

s1.x= 20
s1.y= A
Size of Structure : 8

one integer variable takes 4 bytes and one char variable takes 1 bytes so total size of structure should be 5 bytes but program gives 8 bytes
so how much memory structure take in code ?

Read: Why does sizeof report a larger size than I expect for a structure type, as if there were padding at the end?

Quote:

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Originally Posted by laserlight

Read: Why does sizeof report a larger size than I expect for a structure type, as if there were padding at the end?

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size of structure is 12 bytes and size of structure member is 4 + 4 +1 = 9 but compiler allocate extra 3 bytes that's we call padding

Code:

---

#include <stdio.h> struct point
{
    int x;
    int y;
    char z;
   
}s1;
   
int main()
{
    s1.x = 20;
    s1.y =10;
    s1.z = 'a';
   
 printf("s1.x= %d \n", s1.x);
 printf("s1.y= %d \n", s1.y);
 printf("s1.z= %c \n", s1.z);
 
 printf("Size of struct: %d \n", sizeof(struct point));
 printf("Size of x: %d \n", sizeof(s1.x));
 printf("Size of y: %d \n", sizeof(s1.y));
 printf("Size of z: %d \n", sizeof(s1.z));
    return 0;
}

---

s1.x= 20
s1.y= 10
s1.z= a
Size of struct: 12
Size of x: 4
Size of y: 4
Size of z: 1