6x6 array problem

Hi there! I want to do an 6x6 array which contains the english abc + numbers 0-9 (sum: 36 chars). This will be a polybius cipher. I read words from a txt file (for example apple11) and write its number to a txt file (apple11 = 11 34 34 26 15 54 54). It work, but got wrong results. Thanks

Code:

---

#include <stdio.h>
#include<string.h>
#include<stdlib.h>
#include<ctype.h>


int main(void){


int i,j,k,x;
int tomb[36];


    /*char str[500];
    gets(str);*/


    FILE* fp = fopen ("be.txt", "r");
    char str[500];
    char* filename = "be.txt";
    fgets(str, 500, fp); // ez lesz a fájlból beolvasás


 x=0;
 k=11;


for(i=0;i<=36;i++)


{
 if(i<=6)
 {
      if(i%6==0&&i!=0)
  {
  k+=1;
  tomb[x]=k++;


    }
  else{
  tomb[x]=k++;


      }
 }
 if(i>=6)
 {
      if(i%6==0&&i!=0)
  {


  tomb[x]=k++;
  k+=1;


    }
  else{
  tomb[x]=k++;


      }
 }
 if(i==35)
 {
  tomb[x]=36;
 }
  x++;
}


FILE*  outfile = fopen("ki.txt", "w");


i=0;
while(str[i]!='\0')
  {
 if(!((str[i]>=0&&str[i]<=31)||(str[i]>=33&&str[i]<65)||(str[i]>90&&str[i]<97)||(str[i]>122&&str[i]<=127)))
 {
  if(str[i]>='A'&&str[i]<='Z')
  {
    fprintf(outfile,"%d\n ",tomb[str[i]-'A']);
  }
    if(str[i]>='a'&&str[i]<='z')
    {
      fprintf(outfile,"%d\n ",tomb[str[i]-'a']);
    }


 }


    if(str[i]==' ')
    {
      fprintf(outfile,"%c\n",str[i]);
    }


  i++;
  }


}

---

My first thought is, indent your code properly.

Code:

---

#include <stdio.h>
#include<string.h>
#include<stdlib.h>
#include<ctype.h>


int main(void)
{
  int i, j, k, x;
  int tomb[36];

  /*char str[500];
    gets(str); */
  FILE *fp = fopen("be.txt", "r");
  char str[500];
  char *filename = "be.txt";
  fgets(str, 500, fp);          // ez lesz a fájlból beolvasás

  x = 0;
  k = 11;
  for (i = 0; i <= 36; i++)
  {
    if (i <= 6) {
      if (i % 6 == 0 && i != 0) {
        k += 1;
        tomb[x] = k++;
      } else {
        tomb[x] = k++;
      }
    }
    if (i >= 6) {
      if (i % 6 == 0 && i != 0) {
        tomb[x] = k++;
        k += 1;
      } else {
        tomb[x] = k++;
      }
    }
    if (i == 35) {
      tomb[x] = 36;
    }
    x++;
  }

  FILE *outfile = fopen("ki.txt", "w");
  i = 0;
  while (str[i] != '\0') {
    if (!((str[i] >= 0 && str[i] <= 31) || (str[i] >= 33 && str[i] < 65)
        || (str[i] > 90 && str[i] < 97) || (str[i] > 122 && str[i] <= 127))) {
      if (str[i] >= 'A' && str[i] <= 'Z') {
        fprintf(outfile, "%d\n ", tomb[str[i] - 'A']);
      }
      if (str[i] >= 'a' && str[i] <= 'z') {
        fprintf(outfile, "%d\n ", tomb[str[i] - 'a']);
      }
    }
    if (str[i] == ' ') {
      fprintf(outfile, "%c\n", str[i]);
    }
    i++;
  }
}

---

> for (i = 0; i <= 36; i++)
Then I think you're running off the end of your array.

> if (!((str[i] >= 0 && str[i] <= 31) || (str[i] >= 33 && str[i] < 65)
> || (str[i] > 90 && str[i] < 97) || (str[i] > 122 && str[i] <= 127)))
Then I'm wondering whether this is just a complicated way of saying isalpha() or complete gibberish.

> if (i <= 6)
> if (i >= 6)
So what happens when i == 6 ?



Perhaps you could print every entry of tomb[x] when you're done filling the array.