C program to draw a pyramid

Program accepts 3 integer inputs and I want to draw a pyramid from the side view.
Using the formula for a slope of a line, I end up with two formulas that give the coordinates for the outermost edge of the pyramid at each of its levels.
A hash symbol needs to appear at the edges, top and base with dots everywhere else. My current program is trying to print the pyramid upside down (the loop is supposed to be easier to figure out this way) but eventually I need to make it upright.
What happens now is that the base gets printed properly but then I get an infinite loop of dots starting at the next level after it prints an initial hash to mark the edge. Here is my code:

Code:

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#include<stdio.h>
#include<math.h>
//upside down pyramid
int main(void)
{
    int x = 0, y = 0, z = 0;//dimensions
    scanf("%d %d %d", &x, &y, &z);
    char hash = '#';
    char dot = '.';
    int j = 0;
    for (j = 0; j < 1; j++)//print base first
    {
        for (int i = 0; i < x; i++)
            printf("%c", hash);
        printf("\n");
    }
   
    for (j = 1; j < z; j++)//second to z levels of pyramid
    {
        int right = ceil((x - 1) + (-j)*(x / (2.0*z)));//right line coordinates
        int left = (floor(j*(x / (2.0*z))));//left line coordinates
        int ledge = left;//left edge
        int redge = right;//right edge
        int mid = 0;//middle space
       
        for (ledge = ledge; ledge < (ledge + 1); ledge++);//first #
            printf("%c", hash);
        for (mid = (ledge+ 1); mid < redge; mid++)//dots in between
            printf("%c", dot);
        //for (redge = redge; redge <= redge; redge++)//right hand edge #
        printf("%c", hash);
        printf("\n");//new line to next level
    }
    return 0;
}

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Do you mean to draw a triangle? A pyramid is a 3D structure, and cannot faithfully be rendered using this technique.

You want to render something like this?

Code:

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            #
            #.#
          #...#
          #.....#
        #.......#
        ###########

---

A quick gdb lesson.

Code:

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$ gdb -q ./a.out
Reading symbols from ./a.out...done.
(gdb) list
1        #include<stdio.h>
2        #include<math.h>
3        //upside down pyramid
4        int main(void)
5        {
6            int x = 0, y = 0, z = 0;//dimensions
7            scanf("%d %d %d", &x, &y, &z);
8            char hash = '#';
9            char dot = '.';
10            int j = 0;
(gdb)
11            for (j = 0; j < 1; j++)//print base first
12            {
13                for (int i = 0; i < x; i++)
14                    printf("%c", hash);
15                printf("\n");
16            }
17           
18            for (j = 1; j < z; j++)//second to z levels of pyramid
19            {
20                int right = ceil((x - 1) + (-j)*(x / (2.0*z)));//right line coordinates
(gdb)
21                int left = (floor(j*(x / (2.0*z))));//left line coordinates
22                int ledge = left;//left edge
23                int redge = right;//right edge
24                int mid = 0;//middle space
25               
26                for (ledge = ledge; ledge < (ledge + 1); ledge++);//first #
27                    printf("%c", hash);
28                for (mid = (ledge+ 1); mid < redge; mid++)//dots in between
29                    printf("%c", dot);
30                //for (redge = redge; redge <= redge; redge++)//right hand edge #
(gdb) b 28
Breakpoint 1 at 0x4008b3: file foo.c, line 28.
(gdb) run
Starting program: /home/sc/Documents/a.out
2 3 4
##

Breakpoint 1, main () at foo.c:28
28                for (mid = (ledge+ 1); mid < redge; mid++)//dots in between
(gdb) info locals
ledge = 2147483647
redge = 1
right = 1
left = 0
mid = 0
x = 2
y = 3
z = 4
hash = 35 '#'
dot = 46 '.'
j = 1

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You might think about
1. why ledge is so large.
2. what ledge < (ledge + 1) actually means
3. why there is a ; at the end of line 26

Or consider why

Code:

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for (j = 0; j < 1; j++)//print base first

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is a "loop" that loops only once?