ascii conversion

int d;
scanf("%c", &d);
printf("%d", d);

here giving a alpha value as input and am trying to get ascii value as output why is not working instead it shows address of the char all other ways it works, like getting decimal in char and convert into char.

Quote:

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Originally Posted by zero_code

int d;
scanf("%c", &d);
printf("%d", d);

here giving a alpha value as input and am trying to get ascii value as output why is not working instead it shows address of the char all other ways it works, like getting decimal in char and convert into char.

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You should have your code the other way - scan an integer, print a character.

since the %c in scanf expects pointer to char your d var should be declared as char d

LIke this?

Code:

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#include<stdio.h>

main()
{
    char d;
    scanf(" %c", &d);
    printf("%d\n", d);
return 0;
}

---

Looks better and even works...

You may benefit from reading FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) - Cprogramming.com

And I will add loop so several conversions could be made in the same run...

Code:

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#include<stdio.h>

int main(void)
{
    char d;
    while(scanf(" %c", &d) == 1)
    {
        printf("%d 0x%x\n", d, d);
    }
    return 0;
}

---

Looks better and even works...

You may benefit from reading FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) - Cprogramming.com

And I would add loop so several conversions could be made in the same run...

Code:

---


#include<stdio.h>

int main(void)
{
    char d;
    while(scanf(" %c", &d) == 1)
    {
        printf("%d 0x%x\n", d, d);
    }
    return 0;
}

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relating to the same question suppose if the variable is declared as one type and read as other type in printf is the behavior not undefined. For example

Code:

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float f; printf("%d",f);

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Is this behavior undefined or it is ok? Similarly for char and int types. I am getting confused.

Quote:

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Originally Posted by Satya

Code:

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float f; printf("%d",f);

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The variable must be read as the same type float "%f" therefore your code is incorrect.

Quote:

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Originally Posted by Satya

relating to the same question suppose if the variable is declared as one type and read as other type in printf is the behavior not undefined. For example

Code:

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float f; printf("%d",f);

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Is this behavior undefined or it is ok? Similarly for char and int types. I am getting confused.

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You are correct in that the behavior is undefined.

Quote:

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Originally Posted by c99-draft

7.19.6.1 The fprintf function

...

9 If a conversion specification is invalid, the behavior is undefined. If any argument is
not the correct type for the corresponding conversion specification, the behavior is
undefined.

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