Function prototype in C

Dear all,
I am a newbie in C. Just come across function prototype.
I have a task in write a function prototype for:

• A function that finds the larger of two numbers and returns the result

and i write the following.

Code:

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#include <stdio.h>
/* Function Definition, I do not know whether it is as simplified as definition only*/
void findbig(int num1, int num2)
      {
        If (num1>num2);
                Printf(“%d”,&num1&“is larger”);
        Elseif (num2<num1);
                Printf(“%d”,&num2&“is larger”);
        Else
                Printf(num1&“is equal to”&num2);
        }
Int main()
        {
                Printf(“Compare the 2 numbers”);
                Printf(“Please enter the first number”);
                Scanf(“%d”,&num1);
                Printf(“Please enter the second number”);
                Scanf(“%d”,&num2);
        }

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Looks OK so far, you just need to finish turning your pseudo-code into C code.

Quote:

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Originally Posted by Salem

Looks OK so far, you just need to finish turning your pseudo-code into C code.

---

ok, thanks a lot. But it fulfills the function prototype? i am not clear on this concept.

Well strictly speaking, a prototype is a declaration, not a definition.

So

Code:

---

// declaration / prototype
void findbig(int num1, int num2);

// definition / implementation
void findbig(int num1, int num2) {
  /// code goes here
}

---

Quote:

---

Originally Posted by Salem

Well strictly speaking, a prototype is a declaration, not a definition.

So

Code:

---

// declaration / prototype
void findbig(int num1, int num2);

// definition / implementation
void findbig(int num1, int num2) {
  /// code goes here
}

---

---

Thanks a lot for your help!:)