C++ Help Me!!!!!!!!

I need to take a 3 digit user input and add each individual number in the digit together......its a crack head program but its for school....now im not asking anyone to do my homework for me however i dont know where to start....im confused and aggitated!!!

Code:

---

int main(){
  cout<<"Enter three numbers: ";
  int num1, num2, num3;
  cin>>num1>>num2>>num3;
 
  cout<<num1+num2+num3<<endl;
  return 0;
}

---

or you could enter the three numbers as a string and then add each element by using atoi
[code]
int main(){
cout<<Enter three numbers: ";
char *s;
cin.getline(s);cin.ignore();

int num1, num2, num3;
num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]);
cout<<num1+num2+num3<<endl;
return 0;
}

sorry, it was supposed to look like this

Code:

---

int main(){
  cout<<Enter three numbers: ";
  char *s;
  cin.getline(s);cin.ignore();

  int num1, num2, num3;
  num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]);
  cout<<num1+num2+num3<<endl;
  return 0;
}

---

Hey,
whoever repiled to this the first and second time, your replies are the same, and the program doesnt run.(it has warnings that crash it)
Thanks anyway

Put this at the top of that program and it should work fine,

Code:

---

#include <iostream>
using namespace std;

---

this code is slightly wrong......

Code:

---

int main(){
  cout<<Enter three numbers: ";
  char *s;
  cin.getline(s);cin.ignore();

  int num1, num2, num3;
  num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]);
  cout<<num1+num2+num3<<endl;
  return 0;
}

---

The arguements to getline are wrong and you attempt to input into memory you dont 'own'.
here is the same piece of code with fixes....

Code:

---

#include<iostream>
using namespace std;
int main(){
  cout<<Enter three numbers: ";
  char s[81]
  cin.getline(s,sizeof(s));cin.ignore();

  int num1, num2, num3;
  num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]);
  cout<<num1+num2+num3<<endl;
  return 0;
}

---

You guys are doing it all wrong. He said 3 DIGIT number, and then add each individual digit. so if you entered 125, you would add 1+2+5 wich equals 8.

However, I do not have time to explain the code. So hopefully you guys can work off of this. If I had a few more minutes, I'd write the code for you. Sorry!

how about getting the input a an array of integers and adding the integers?

If you can't get the input as seperate numbers or in an array then you can seperate the individual digits using the / and % operators (divide by 100 to get first digit and get remainder using %, divide remainder by 10 to get second digit..etc).

a three digit number is a meaningless concept to the compiler. The input could be stored as a string, an int, a double, a float, or any number of variable types. If the requirement was to enter an integer consisting of three digits, then the concepts as presented so far would be off base.

char sEntry[4];
int entry;
cout << "enter a 3 digit number" << endl;
cin >> sEntry;
cout << "enter another 3 digit number" << endl;
cin >> entry;

However, here's a completely different approach that doesn't require conversion from int to string or char to int or any of that stuff:

int num1, num2, num3, i, temp;
int total = 0;
temp = entry;

num3 = temp % 10;
temp = temp/10;//this is integer math, not routine math//
num2 = temp % 10;
num1 = temp/10;
total = num1 + num2 + num3;
cout << "the sum of the digits of the number " << entry << " is " << total << "." << endl;

Oops, looks like Zen beat me to the punch as I was waylaid in my posting my response. Oh well.