joining codes

I need help with completing and some codes together
Key aims: 1. The user can select a departure station
2. The user can select an arrival station
3. the user can select either single or return journey.

i need the code to be able to show the result of the arrival and departure station and a way to count the stops so i could add to the calculation.

Code:

---

#include <stdio.h>

void station1()
{
    printf( "Ashford Station" );
}
void station2()
{
    printf( "Brentworth Station" );
}
void station3()
{
    printf( "Canonbury Cross Station" );
}
void station4()
{
    printf("Dowgate Station");
}
void station5()
{
    printf("Edbury Station");
}
void station6()
{
    printf("Fenchurch Street Station");
}
void station7()
{
    printf("Gresham Station");
}
void station8()
{
    printf("Hampstead Station");
}
void station9()
{
    printf("Islington Station");
}
void station10()
{
    printf("Jamaica Road Station");
}
int main()
{
    int input;

    printf( "1. Ashford Station\n" );
    printf( "2. Brentworth Station\n" );
    printf( "3. Canonbury Cross Station\n" );
    printf( "4. Dowgate Station\n");
    printf( "5. Edbury Station\n");
    printf( "6. Fenchurch Street Station\n");
    printf( "7. Gresham Station\n");
    printf( "8. Hampstead Station\n");
    printf( "9. Islington Station\n");
    printf( "10. Jamaica Road Station\n");
    printf( "11. Exit\n" );
    printf( "Arrival Station:" );
    scanf( "%d", &input );
    printf("Depature Station:");
    scanf("%d",&input);
    switch ( input ) {
        case 1:
            station1();
            break;
        case 2:
            station2();
            break;
        case 3:
            station3();
            break;
        case 4:
            station4();
            break;
        case 5:
            station5();
            break;
        case 6:
            station6();
            break;
        case 7:
            station7();
            break;
        case 8:
            station8();
            break;
        case 9:
            station9();
            break;
        case 10:
            station10();
            break;
        case 11:
            printf( "Thanks\n" );
            break;
        default:
            printf( "Invaild input, quitting!\n" );
            break;
    }
    getchar();

}

---

I have a price code which i can't complete

Code:

---

#include<stdio.h>
int main(void)
{float  ticketcost=2.00f, returncost=0.0f, stops =0.0f, singlecost=0.0f, priceofjourney =0.0f;

    {int choice;
    printf("\nEnter Either 1 for Single Journey or 2 for Return Journey:");
    scanf("%d", &choice);
    if (choice==1)
    {
        printf("\nSingle Journey:");
        scanf("%f", &singlecost);
        }
        else if (choice==2)
      {
            printf("\nReturn Journey:");
        scanf("%f", &returncost);
        }
        else
        {
            printf("\nInvalid Option");
        }
    {float  ticketcost=2.00f, returncost=0.0f, stops =0.0f, singlecost=0.0f, priceofjourney =0.0f;


  singlecost=ticketcost*stops;
  returncost=singlecost * (singlecost/2);
  printf("\nPrice of single journey = %.2f\n\n", singlecost);
  printf("\nprice of return journey = %.2f\n\n", returncost);

 getchar();

return 0;}
    }
}

---

I would really appreciate any advice or help.
thanks

In main you are assigning departure station and arrival station to the same variable:

Code:

---

printf( "Arrival Station:" );
scanf( "%d", &input );
printf("Depature Station:");
scanf("%d",&input);

---

so you are losing the 'arrival station' value. Once you keep the two values separate you can calculate the number of station by arrival - departure. If it's negative make it positive.

Please, please, please ... learn to use arrays!

Code:

---

#include <stdio.h>

int main(void) {
    int input, i;
    const char *station[] = {
        "Ashford Station",        "Brentworth Station",
        "Canonbury Cross Station", "Dowgate Station",
        "Edbury Station",          "Fenchurch Street Station",
        "Gresham Station",        "Hampstead Station",
        "Islington Station",      "Jamaica Road Station"
    };

    for (i = 0; i < 10; i++) {
        printf("%d. %s\n", i + 1, station[i]);
    }
    printf("11. Exit\n");
    /* code commented out
    ** because it has no effect other than
    ** cluttering the display
    printf("Arrival Station: ");
    scanf("%d", &input);
    */
    printf("Departure Station: ");
    scanf("%d", &input);
    if ((1 <= input) && (input <= 11)) {
        if (input == 11) printf("Thanks\n");
        else printf("%s\n", station[input - 1]);
    } else {
        printf("Invalid input, quitting!\n");
    }
    getchar();
    return 0;
}

---

If you use an array to store all those stations and 'for loops' to read from it, it'll make it so much easier to print/read from them

C++ Tutorial - 10 - Beginning Arrays - YouTube

once you figure it out it'll make your life much easier and your code a lot better

thanks for the help, i'm stuggling to caculate the diffrence between the arrival and departure, any ideas with for that?

Quote:

---

Originally Posted by nonoob

In main you are assigning departure station and arrival station to the same variable:

Code:

---

printf( "Arrival Station:" );
scanf( "%d", &input );
printf("Depature Station:");
scanf("%d",&input);

---

so you are losing the 'arrival station' value. Once you keep the two values separate you can calculate the number of station by arrival - departure. If it's negative make it positive.

---

please how would i calculate that? thanks