issue with point to array.

My function is this....

Code:

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struct names *open_classes_taken(int *name_count, int *class_count[]);

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it returns a structure for me. And it uses an integer that i'll need later which is the first part. The second part it uses is an array of integers. Which I'll use later

Code:

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int main(){


    int name_count = 0;
    int class_count[10] = {0};
    struct names *all;
 
    all = open_classes_taken(&name_count, &class_count[]);

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there is my main that is needed

So my function is working. Getting an error of "syntax error before ] token" when I call my function. Trying to use it as a pointer. What am I doing wrong?
I feel like this is a rookie question, but I was surfing the web and couldn't find much on it for what I'm trying to do.

Quote:

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Originally Posted by mgracecar

it returns a structure for me.

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It returns a pointer to a struct names object.

Quote:

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Originally Posted by mgracecar

So my function is working.

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You don't actually know that until you test, and you haven't tested because of the problem that you are facing ;)

Quote:

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Originally Posted by mgracecar

Getting an error of "syntax error before ] token" when I call my function. Trying to use it as a pointer. What am I doing wrong?

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Your open_classes_taken function's second parameter is a pointer to a pointer to int. You have an array of 10 ints. I suspect that you actually want your open_classes_taken function's second parameter to be a pointer to int:

Code:

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struct names *open_classes_taken(int *name_count, int *class_count[]);

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Then you call it as:

Code:

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all = open_classes_taken(&name_count, class_count);

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Quote:

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Originally Posted by laserlight

You don't actually know that until you test, and you haven't tested because of the problem that you are facing ;)

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Well actually I tried the function without the parameter and it was working. I just added the parameter because I realized I need to use it to know how many spots there are in the structure. And that's where I got my problem :tongue:

and ok sorry on that. You're right. It returns a pointer to a structure.
Anyways that part is working. I went ahead and checked the structure after it was returned and it's working perfectly :)

And on the last part. What I'm wanting is to use this as a pointer to an array of ints. I'm going to need an int returned in that for each row of names.
So now I think I see what you mean on the part....

Code:

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all = open_classes_taken(&name_count, class_count);

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And that would be all I would need to change I would think? If so I'm getting an error of argument 2 is passed from incompatible pointer type.


hmm. Any suggestions? I understand pointers fairly well until it gets into pointers to pointers. lol.

Thanks for your help so far. Correct me if I'm misunderstanding you. And any help on my current error would be appreciated.

Oh dear, I forgot to modify the code snippet. Basically, I'm suggesting that your function be declared as:

Code:

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struct names *open_classes_taken(int *name_count, int *class_count);

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Works perfectly.
Thanks a lot for your help. ;)