find the digits

I want to transform a number into a vector of it's digits. For example, 123 will be 1 2 3.
I came up with this code:

Code:

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void transform(const uint & x , deque<uint> & output)
{
  if ( x != 0 )
    {
      uint x_stripped = (x/10)*10;
      uint digit = x - x_stripped;
      output.push_front(digit);
      transform(x_stripped / 10, output);
    }
}

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My question is, is there better way to do this? taking x and divide then multiply by 10 is a bit irksome for me.

You could try:

Code:

---

void transform(const uint& x , deque<uint>& output)
{
    do
    {
        output.push_front(x % 10);
        x /= 10;
    }
    while (x != 0);
}

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Quote:

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Originally Posted by laserlight

You could try:

Code:

---

void transform(const uint& x , deque<uint>& output)
{
    do
    {
        output.push_front(x % 10);
        x /= 10;
    }
    while (x != 0);
}

---

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laserlight, x/=10 wouldn't work because x is const. Maybe I could create a temp variable instead.

Quote:

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Originally Posted by nimitzhunter

laserlight, x/=10 wouldn't work because x is const. Maybe I could create a temp variable instead.

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Oh yeah, I did not notice that. Just change to use pass by value since passing by const reference is not likely to gain you anything here.

Quote:

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Originally Posted by laserlight

Oh yeah, I did not notice that. Just change to use pass by value since passing by const reference is not likely to gain you anything here.

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Thanks alot for your help, laserlight. It works perfectly :-D.