printing last 2 characters of a long/string

Hi

Hope you can assist with a very basic C question. Im trying to print the last two characters of a long obtained from a table. lets say the value is 130. How do i print just the 30.

This is the piece of code:

sprintf(unidades_standar,"%ld:%02ld",standar/60,standar%60)

So in the section after the ':' where the %02ld is, i need this to print the last two decimal values. Hope it makes sense

Cheers

If you want to print out the last two char's in a string of numbers:

Code:

---

char n1, n2;
char str[] = {"130"];
n1 = str[strlen(str)-1];  //if you have removed the newline char from the string

n1 = str[strlen(str)-2];  //if you have not removed the newline char from the string str.

//same thing for n2, just subtract one more than you did for n1 to be correct

// if it's in a number, then:

int n1, n2, number = 130;

n1 = number % 10;  //gets the right most digit from "number"  (the 0)
number /= 10;  //divide number by 10
n2 = number % 10;  //gets the new right most digit from "number" (the 3)

---

Or you could simply display modulo 100 of the integer...

Thanks

That helps a lot...