entering a long character

I cant get this code to work, what am i doing wrong.

I want to enter a model number and print an output depending on the answer.

Please help and advise. Thanks.

Code :-
#include<stdio.h>
#include<conio.h>

int main (void)

{
clrscr();

char a[6];

printf("Please enter the Model Number? ");
scanf("%s", &a);

if (a == 123abc ) printf("Shelf 5");
if (a == 456def ) printf("Shelf 4");
if (a == 12ab54 ) printf("Shelf 3");
if (a == 76fred ) printf("Shelf 2");
if (a == 21jufs ) printf("Shelf 1");

Return 0;

}

1) I think it should be char a[7] to make room for the '\0' appended to strings
2) You don't need the '&' in front of the 'a' in the scanf() as arrays are addresses anyway (and '&' means address of)
3) I'm not sure you can compare stings like that - you'l probably have to use 'strcmp(a, "123abc")' returns 0 if 1 if false

Hope that helps (if indeed its right =) )

Peaches is spot on, Try this:

Code:

---

#include <stdio.h>
#include <string.h>

int main (void)

{

char a[7];  // needs one extra for the \0

clrscr();

printf("Please enter the Model Number? ");
scanf("%s", a); // dodgy scanf!!!

if (!strcmp(a, "123abc" ))
        printf("Shelf 5");
else if (!strcmp(a, "456def" ))
        printf("Shelf 4");
else if (!strcmp(a, "12ab54" ))
        printf("Shelf 3");
else if (!strcmp(a, "76fred" ))
        printf("Shelf 2");
else if (!strcmp(a, "21jufs" ))
        printf("Shelf 1");
else
        printf("Unknown");

return 0;

}

---

The if else is better as you only check enough to find the right one, also I added an option for incorrect entries.