Self referencing structure

I have a structure that contains a pointer to another instance of itself (like a linked list). However I'm getting an error that says I'm missing a ";" when I'm not...

Code:

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typedef struct IOD {
  char Name[11];
  int  Request_Type;
  char *Transfer_Buffer;
  int  *Transfer_Counter;
  IOD  *Next_IOD;
} IOD;

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I think I need some sort of prototype struct but I'm unsure how to do this.

The problem is that the typedef name IOD only exists after the struct definition.

Option #1:

Code:

---

typedef struct IOD IOD;

struct IOD {
  char Name[11];
  int  Request_Type;
  char *Transfer_Buffer;
  int  *Transfer_Counter;
  IOD  *Next_IOD;
};

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Option #2:

Code:

---

typedef struct IOD {
  char Name[11];
  int  Request_Type;
  char *Transfer_Buffer;
  int  *Transfer_Counter;
  struct IOD  *Next_IOD;
} IOD;

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I have a function that expects a int * as a parameter. I have an int inside a structure.

Code:

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typedef struct myStruct {
  int myStructInt;
} myStruct;


myStruct test_struct;


void test_fun(int * myInt) {
  // yadda yadda
}

int main() {
  test_fun(??????????);
}

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How do I pass the address of the structure element? I tried &(test_struct.myStructInt).

Quote:

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Originally Posted by Bladactania

How do I pass the address of the structure element? I tried &(test_struct.myStructInt).

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That should work, though it can be simplified to &test_struct.myStructInt.

No, that's completely wrong now. The structure doesn't contain a pointer to a structure any more. You took it out and declared a type. Go back and read laserlight's post again.


Quzah.