void * to char *

Hi there, i got this function : and i most convert the (void*) returned by the function in a (char *). I tried many things, but nothing could go past the compiler.. can anyone give me a hint on this?

my last try was something like: (char*)function_result
where function_result is the void* returned by the function.

Code:

---

typedef struct
{
  int nombre_prefere;
  char allo[50];         
  char *chaine_dynamique;
} MaStructure;

void *recuperateur_de_allo(void *donnees)
{
  MaStructure *d = donnees;
  return d->allo;
}

---

I give you my big thanks! :)

It helps if you make a small example of what you're trying to compile.

Code:

---

#include<stdio.h>
struct foo
{
    char bar[ 10 ];
};

void * baz( void * foo )
{
  return ((struct foo *)foo)->bar;
}

int main( void )
{
    struct foo bar;
    char *fbb;

    fbb = (char *) baz( &bar );
    return 0;
}

---

Quzah.

Sorry, your right. Here an exemple that represent my problem.

Code:

---

#include<stdio.h>
struct foo
{
    char bar[ 10 ];
};

void * baz( void * foo )
{
  return ((struct foo *)foo)->bar;
}

char *main( (*baz)(void *))
{
    struct foo bar;

    return = (char *) baz( &bar );
}

---

Look at my example, and compare it to yours. What parts are you confused about?


Quzah.

Clue: This is not how to call a function

Code:

---

return = (char *) baz( &bar );

---

at the line: return = (char *) baz( &bar );

i get this error : 'void' term to non-'void'

Quote:

---

Clue: This is not how to call a function

---

event with this clue i just can't see it right now :(. I been scripting 36 hours straight for school. heh

Thx for helping me guys.

Why did you change that line from what I had? You must have had a reason. What was it?


Quzah.

i changed the "char *main( (*baz)(void *))" too. it's exactly like what i use it in my program. Since I'm still a beginner, i prefer showing an example really similar to the real thing. :)

Quote:

---

Originally Posted by Loukoulaylay

I been scripting 36 hours straight for school. heh

---

In C? Are you sure? Maybe it is time to quit before you grow old!

Just kidding. My point is you are complaining about how to typecast a return value, but you are not really using the return value at all. That would be:

Code:

---

struct foo bar;
char ptr*;
ptr = (char *) baz( &bar );
return 0;

---

The return value of main is not used during the execution; it's for the OS, and it should be an int, not a char. Which brings us to this:

Code:

---

char *main( (*baz)(void *))

---

What is that supposed to mean???

Quote:

---

In C? Are you sure? Maybe it is time to quit before you grow old!

---

I must agree with that. That is the last time i take a C course as an option at University..heh

yeah, i do know that. I just used the main for the example, but in my "real case" it's an another function which return char *main( (*baz)(void *)).

so i guess that's not my problem :(, but you guys still gave my clues. My thinking wasn't all wrong since i did the same thing as you when i tried ^^.

In any case, "return=" is non-sensical.

Using a (char*)typecast should be enough if you have the rest of your syntax in order.

Next time don't wait til the end of the semester to start coding!

lol i didn't wait till the end. i Just haev 3 big project to do during the semester .. and i just received the last one. I still got 1 week to finish it, but i wan to clear it right aways. :)