Array initialization with int variable

How can I initialize an index giving its size thru an int variable aiming the something like the above:

int x=10;

char test[x];


Thank you,
Thiago Santana

std::vector<T> v(size);
But if it's just a string, use std::string.

Thanks Elysia,

But quite not what I am looking for. I just want to inform the simple array size being the size an int variable. It has to be a very simple array like the one I have sample on my original post.

Thank you,
Thiago Santana

Are you looking into making a dynamically sized array?
For example, setting a size and making an array that big, or are you looking for some string?
I don't get your question really.

You can't do that legally with a variable. If you know x will be 10 (or some other number) when you write the program use this:

Code:

---

const int x=10;

char test[x];

---

Some compilers allow your original code as an extension, but as I said that's not strictly legal in C++.

If the size is not a constant (and you want to use standard C++), then you have no choice but to use a dynamic array container. The best choice for that is vector (or string) as shown by Elysia. You can also use new[]/delete[], but that would make sense only if your instructor doesn't allow you to use vector for some reason.

Thanks Daved and Elysa for the inputs. That helps me.