Pass struct array to function

How am I to pass an array struct to another function?
Can someone give me an example.
I do not want a ready-made program. Just some help.
I do not really follow how to pass an array structure to a function.


Please help me.
I have not written any code as yet coz, I don't know how to do it.

Thanks

Arrays are usually passed by pointers. Turn your array of structs into a linked list, where each node has a pointer to the next node. Then you just pass the function a pointer to the first node.

Or you can just pass the array name into the function, because arrays are passed by pointer and you don't have to worry about a linked list.

I guess the question is, have you never passed an array into a function before?

Arrays are actually always passed by pointer, so this is not so hard. If your declaration looks like this:

Code:

---

struct example ray[3];

---

You can use either of these in a function prototype:

Code:

---

void testfunc (struct example *ray);
void testfunc (struct example ray[3]);

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Here's a little demo:

Code:

---

#include <stdio.h>

struct example {
        char *ptr;
        int ID;
};

/* this needs to be global since testfunc does not copy, it just links */
char data[3][8]={"one", "two", "three"};

void testfunc (int size, struct example ray[size]) { 
        int i, x=0;
        for (i=0;i<size;i++) {        /* populate the array */
                ray[i].ptr=data[x]; x++;
                ray[i].ID=i+1;
                if (x>2) x=0; }
}

int main() {
        int num = 6, i;
        struct example ray[num];
        testfunc(num,ray);
        /* now back in main... */
        for (i=0;i<num;i++) printf("%d %s\n",ray[i].ID,ray[i].ptr);       
        return 0;
}

Output:
1 one
2 two
3 three
4 one
5 two
6 three


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Again, testfunc could have used *ray instead of ray[size].

Yes I have never passed an array to a function :p

Anyway thanks for all the help