Hangman Help - Code included

Hi,

I need help with me Hangman code below please. I have only been programming for 5 weeks so my lecturer isn't concerned with memory efficiency etc, only that the program works. The part that I am stuggling with is when the user enters the letter and then for it to be checked against the array. I can get it to check the array and print out if it finds the letter, however if it doesnt find the letter, i am having problems......if you could please look at my code and let me know....thanks...

Code:

---


#include <conio.h>
#include <stdio.h>
#include <stdlib.h>

int main()

{

char words[10][10];  /*array to store imported file strings*/
int buffer;          /*temporarily stores random word from words array*/
char gameword[10];    /*array to store playable gameword*/
int i;                /*counter*/
int option;          /*Menu option*/
int lives;            /*Number of game lives*/
char letter;                            /*stores letter guessed*/
char guessedword[10];  /*all letters will be set to "*" and changed as the user guesses correctly*/
int counter;
int number;
int x;



FILE *file;

file = fopen("test.txt", "r");

i = 0 ;
while(!feof(file))

{

        /* loop through and store the numbers into the array */
        fscanf(file, "%s", &words[i]);
        i++;
}

fclose(file);

srand(time(NULL));              /*These 3 lines of code generate a random*/
buffer=words[(1 + rand() % 4)];  /*word from the imported file into the buffer*/
strcpy(gameword, buffer);        /*and then copies it into a playable array*/
number = strlen(gameword);

for ( counter = 0; counter < number; counter++)
{
guessedword[counter] = *"*";    /*sets all guessedword characters to "*" */
}

/*Menu text*/

printf("Hello and Welcome to Hangman in C\n\n");
printf("Please choose one of the following options: \n\n");
printf("1. Beginner Difficulty - 9 Lives\n");
printf("2. Intermediate Difficulty - 6 Lives\n");
printf("3. Hard Difficulty -  3 Lives\n");
printf("4. Exit Game\n\n");
printf("Make your selection:  ");
scanf("%d", &option);


if (option == 1)        /*Determines number of games lives depending upon*/
                        /*user input*/
{
lives = 9;
}

        else if (option == 2)
        {
                lives = 6;
        }

        else if (option == 3)
        {
        lives = 3;
        }

        else if (option == 4)
  {
    return 0;
  }

system ("cls");                    /*Clears screen*/

if (option == 1)        /*Displays message depending upon user input*/

{
printf("\nSo you've gone for the easy option - What's the matter, feeling chicken?\n\n ");
}

        else if (option == 2)

  {
  printf("So you're a middle of the road type of guy then!\n\n ");
  }

  else if (option == 3)
  {
  printf("So you've gone for the Hard difficulty - Good luck, you are going to hang\n\n");
  }

printf("%s\n\n\n", gameword);
printf("%s", guessedword);


printf("Please choose a letter ");
scanf("%s", &letter);




for (x=0; x<number; x++)

{

if (letter == gameword[x])
{
guessedword[x] = letter;
printf("You have made a correct guess\n\n%s", guessedword);
}

---

So you need to count how many letters were placed during your for-loop (i.e., at the start you set letters_this_time = 0 and then when you find a letter add one to the count) -- if, at the end of the for loop, you placed 0 letters then it's a miss.

Thanks for the response, but it doesn't seem to work. Is this how you mean:

Code:

---


for (x=0; x<number; x++)

{
letters_guessed_this_time == 0;

if (letter == gameword[x])
{
guessedword[x] = letter;
printf("You have made a correct guess\n\n%s", guessedword);
letters_guessed_this_time++;
}

if (letters_guessed_this_time == 0)
{
printf("Incorrect guess");

printf("%d", letters_guessed_this_time);

}
}

---

When I compile that, it prints an error message off for each character in the word. So if I had an 8 letter word, it would print off the error message 8 times as it scans through the string on the for loop. Is there a way to limit the scope of the variable letters_guessed_this_time to only 1 integer irrespective of the length of the word and therefore the for loop?

Thanks again!

I believe he had something like this in mind:

Quote:

---

Originally Posted by darren78

Thanks for the response, but it doesn't seem to work. Is this how you mean:

Code:

---


for (x=0, letters_guessed_this_time ==0; x<number; x++)

{

  if (letter == gameword[x])
  {
      guessedword[x] = letter;
      printf("You have made a correct guess\n\n%s", guessedword);
      letters_guessed_this_time++;
  }
  else
  {
      printf("Incorrect guess");
  }
    printf("%d", letters_guessed_this_time);
}

---

When I compile that, it prints an error message off for each character in the word. So if I had an 8 letter word, it would print off the error message 8 times as it scans through the string on the for loop. Is there a way to limit the scope of the variable letters_guessed_this_time to only 1 integer irrespective of the length of the word and therefore the for loop?

Thanks again!

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