Getting just the filename from a path

i need to extract just the filename from a full path when using the saveFileDialog.

i have noticed in the openFileDialog they give the "SafeFilename" to do that job but it is not there in the saveFileDialog options.

so i guess i need to use either basic string handling or maybe stringbuilder here ?

however my string handling experience in c# is not good i would like to know how to achieve this.

if my path is

c:\users\me\test\filename.txt

how can i strip just the "filename.txt" part to save in another string ( or even just chop the exsiting string as it is not needed after this point)

thanks

Path.GetFilename(...)

or if u wanna do it string search way:

Code:

---

string[] split = path.Split('\\');
string filename = split[split.Length - 1];

---

and of course check for errors in the input string.

thanks Bling - sorted :)

Perhaps something like

Code:

---

            OpenFileDialog op = new OpenFileDialog();
            op.ShowDialog();

            MessageBox.Show(op.FileName.Substring(op.FileName.LastIndexOf("\\") + 1));

---

Don't do it by hand when there's excellent classes in System.IO.Path for you!

Hehe Cool ^ Learn something new about the framework every day.

It never seizes to amaze me how lazy people so persistently do things the hard way, even though it means that it goes against their lazy nature.

Google, people. GOOGLE. First result. Or second for more concise results.

shift+tab, grab the mouse, move 45deg up-right, type, press <enter>, move mouse 45dg up donwn and click on link. Read link. Copy paste.... too much work.
Moral: lazy people are doomed