Test your knowledge

What is the last value displayed when this code is run?

Code:

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int *secret;
int j;
secret=new int[10];
secret [0]=[10];       

for (j=1;j<10;j++)
{
        secret [j]=secret[j-1]+5;
}

for(j=0;j<10;j++)
{
        cout<<secret[j]<<" "<<endl;
}

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Is it 45, 50, 55, 60, or 80 ?

It can't compile; it can't run; it doesn't print out anything. (That code is syntactically invalid.)

Soma

Code:

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int *secret;

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That is also very dangerous... pointer not assigned on initalization, should be at least NULL

Quote:

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Originally Posted by swgh

Code:

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int *secret;

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That is also very dangerous... pointer not assigned on initalization, should be at least NULL

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I would certainly not assign it a value and then immediately assigning it something else. Simply combine the declaration and the assignment in such a case:

Code:

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int *secret=new int[10];

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or better yet, use a statically sized array in this case, and avoid the memory leak:

Code:

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int secret[10] = {10};

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(combines lines 1, 3 and 4).

btw, the bug is here:

Code:

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secret [0]=[10];

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[10] should be just 10. That and the fact that the code needs to be placed within an actual program i.e. main, and have using and include statements added.

Well at least this wasn't one of those ones with undefined behaviour for a change, like asking what is the value of ++x + ++x...

not to be a jerk but.

FAIL