pointer dereference

Code:

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int x[] = {1,2,3,4,5}; int *ptr, **ptr2; ptr = x; ptr2 = &ptr;

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referring to the above code sample, how do you update x[2] to 10 using "ptr2"?

Is it **(*ptr2+2) = 10 or **(ptr2+2) = 10 or *(*ptr2+2) = 10 or *(&ptr2+2) = 10.

As per my understanding,its *(*ptr2+2) = 10
Just want to confirm it.

>> As per my understanding,its *(*ptr2+2) = 10
>> Just want to confirm it.

Why not code it yourself and test it? I did! ;^)

It shows *(*ptr2+2) = 10