What's wrong with the "friend template" snippet

I am following the http://www.parashift.com/c++-faq-lit...html#faq-35.16 to write the snippet below:

Code:

---

template<typename T>
class Foo {
public:
    Foo(const T& value = T());

    friend T bar (T x){
        return x;
    }

private:
    T value_;
};

int main(){
    Foo<int> obj;
    bar<int>(3); //correct if I comment this line

    return 1;
}

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According to the link, if I define the friend function body within the class, complier won't complain anything.
It IS true if I don't call

Code:

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bar<int>(3);

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But if I do call the function it complains:

Quote:

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g++ -c -g main.cc -o main.o
main.cc: In function `int main()':
main.cc:17: error: parse error before `>' token
make: *** [main.o] Error 1

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So what is the correct way to call bar?

Quote:

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Originally Posted by V

So what is the correct way to call bar?

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bar(3) works or me, but frankly, I cannot explain exactly what's happening.

According to the FAQ there are two ways, define bar inline or define it outside the class.

It appears that if you define it outside as a template function as shown in the example, bar is template function.

If defined inline, the compiler generates a non-template function for each instantiation of Foo with a different type - here int bar(int) - and there still won't be linker errors because the function exists for this type of Foo, except bar won't be a template function and you can't use it with the template syntax.