Need help with fibonacci sequence in c

Below is my code. My problem is that when i run it, it asks me how many times i want to run, i input my number and hit enter.... and nothing else happens.

Code:

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#include <stdio.h>


int main() {


int num1 = 0;
int num2 = 1;


int num_t = 0;
printf("Enter the number of times you want the Fibonacci sequence to be run: \n");
scanf("%d", &num_t);




int num_r = 0;


while(num_r <= num_t); {
    printf("Here is the next number: %d ", num1);
    printf("Here is the next number: %d ", num2);
    num1 = num1 + num2;
    num2 = num1 + num2;
    num_r += 1;






}
return 0;


}

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please PM me if you've replied with a possible fix

On line #21, that semicolon says to the compiler that your while statement ends there, without any instructions. That results in an infinite loop if you input a number >= 0. Yes, C is weird like that sometimes. Remove it.

thanks so much!

IT WORKED Thanks so much, I have been cracking my head open for weeks with this lol thanks so much

Here is an alternate version. For 32 bit signed integer, max input is 46.

Code:

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#include <stdio.h>

int main() {
int num1 =  1;    /* fib(-1) */
int num2 = -1;    /* fib(-2) */
int num_r;
int num_t;
int temp;
    printf("Enter the number of times you want the Fibonacci sequence to be run: \n");
    scanf("%d", &num_t);
    for(num_r = 0; num_r <= num_t; num_r += 1){
        temp = num1;
        num1 = num1 + num2;
        num2 = temp;
        printf("%d\n", num1);
    }
    return 0;
}

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or

Code:

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#include <stdio.h>

int main() {
int num1 =  1;    /* fib(-1) */
int num2 = -1;    /* fib(-2) */
int num_r;
int num_t;
    printf("Enter the number of times you want the Fibonacci sequence to be run: \n");
    scanf("%d", &num_t);
    for(num_r = 0; num_r <= num_t; num_r += 1){
        num1 = num1 + num2;
        num2 = num1 - num2;
        printf("%d\n", num1);
    }
    return 0;
}

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