sizeof function confusion

Hello,

i learning to code without any prior experience to it whatsoever. Here is my confusion regarding the function sizeof().

So, when declaring an array, the name of array is just a pointer to its first element. Then, why is the output in the following code is 12 and not 4, which is the actual size of the variable "movie1"?

Code:

---

int main()
{
    char movie1[] = "Hello World";


    printf("%d", sizeof(movie1));


    return 0;
}

---

A couple of things.

Despite the function-like syntax, sizeof is an operator (like + or -), not a function.
The parentheses are only required when referring to types.

Eg.

Code:

---

#include<stdio.h>
int main() {
  char movie1[] = "Hello World";
  printf("%zd\n", sizeof movie1);
  return 0;
}

---

> So, when declaring an array, the name of array is just a pointer to its first element
Not quite.
The name of the array is the name of the array.
The "array becomes a pointer to the first element" happens in most circumstances, but not all.
One example as you have found is when using an array name in a sizeof expression.
Arrays and Pointers

Thank You, Salem.