date valid program

I have a question with my date valid program, when I put in the date in the format MMDDYY it is supposed to check the MM (month), the DD (day), and the year (year). When I put in the date (ex. 121201) it doesn't go to either of the printf statements instead when I press enter it just goes the next line down without any printf output. When the program worked before, if I put in 121201 it would come out as 12121 which I am not sure why it does that. Any solutions that would get this program to work?

Code:

---


#include <stdio.h>

int main(void) {

 int month;
 int day;
 int year;



printf("Enter the date in the format MMDDYY: ");
scanf ("%d%d%d", &month, &day, &year);

  if( month <= 12 && month > 00 && day <= 31 && day > 00 && year >= 00 && year <= 99 )
 
    printf("\n%d%d%d the date is valid\n\n", month, day, year);

  else
  printf("\n%d%d%d the date is not valid\n\n", month, day, year);


 return 0;
}

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Quote:

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Originally Posted by tiger6425

I have a question with my date valid program, when I put in the date in the format MMDDYY it is supposed to check the MM (month), the DD (day), and the year (year). When I put in the date (ex. 121201) it doesn't go to either of the printf statements instead when I press enter it just goes the next line down without any printf output. When the program worked before, if I put in 121201 it would come out as 12121 which I am not sure why it does that. Any solutions that would get this program to work?

Code:

---


#include <stdio.h>

int main(void) {

 int month;
 int day;
 int year;



printf("Enter the date in the format MMDDYY: ");
scanf ("%d%d%d", &month, &day, &year);

  if( month <= 12 && month > 00 && day <= 31 && day > 00 && year >= 00 && year <= 99 )
 
    printf("\n%d%d%d the date is valid\n\n", month, day, year);

  else
  printf("\n%d%d%d the date is not valid\n\n", month, day, year);


 return 0;
}

---

---

Are you getting a black screen? If so, it's because the construction of your code; scanf() is waiting for the next set of 2 numbers. One way around this is to enter your dates like this: 09 02 10 and it'll work. Since it seems like you are just starting out, I would never use all the conditions in one line, instead break them up into separate lines and then test the condition.

The way you have your scanf() presented, it can never work in this format: MMDDYY.

How does

Code:

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scanf("%d%d%d",&month, &day, &year);

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know that the month, day, and year are two digits each?

Try

Code:

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scanf("%2d%2d%2d",&month, &day, &year);

---

Jim

Ok, I changed the printf statement

Code:

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printf("Enter the date in the format MM DD YY: ");

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where in between the three date types in the command prompt I put in a space
when I entered between the MM DD YY.

The scanf("%2d%2d%2d",&month, &day, &year); did change the results since I entered
a date which would be 09 13 01 in scanf. The command prompt reads the 09 13 01 as 913 1. With a black space instead of a 0 in front of 9 same with before 1.
I don't know how the command prompt is displaying the date as 9131. Is there a piece of code
that would include the 0's?

I also need to come up with a piece of code that would show that the year is a leap year in the
2000 generation that 2000 would show as YY 00 lets say leap % 20 or leap % 100 to prove that the year
would be a leap year.

I image of the results from the last post.