fastest way to change a time_t into a string

i need to change the string of numbers returned by time() (in a time_t type variable) into a string type varaible. what is the best way to do this?

ctime() or strftime() via localtime() or gmtime() if you need more control.

http://cppreference.com/stddate.html

more detail on the above functions

strftime() is a better choice than ctime() or asctime() simply because ctime() and asctime() return a pointer to a local static buffer that will be overwritten during each subquent call. Of course if you are only dealing with one date then thats perfectly fine ;)

i don't think you understood what i meant. time returns time_t which contains the number of seconds since 1/1/1970 i need to convert that number into a string (just the same thing, but i need it as a string type). sorry for late reply

sprintf() is the easist way :)

Code:

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sprintf(buffer, "%u", (unsigned) time(NULL));

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Where buffer of course is an array of characters.

Quote:

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Originally Posted by whackaxe

i don't think you understood what i meant. time returns time_t which contains the number of seconds since 1/1/1970 i need to convert that number into a string (just the same thing, but i need it as a string type). sorry for late reply

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Such an operation is inherently nonportable. time_t is an arithmetic type, but the only operation defined for it is a comparison to (time_t)-1. So any integer-string conversions would be relying on a specific representation of time_t. However, because most implementations use unsigned long or similar, sprintf should work.

Code:

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time_t present = time(0);
sprintf(buffer, "%lu", (unsigned long)present);

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