SOS no errors, but program not running

Hey there

I'm new to C programming, fluent in Java. I have a program that I need to create for part of an assignment. This is what I have programmed but for some reason, the program does not allow me to make a second selection, and terminates. Any advice would be appreciated.

Code:

---

#include <stdio.h>
#include <math.h>
#define pi 3.14159
int main()
{

double al=2.70; /*2.70g/cm3*/
double st=7.85;
double cu=8.94;
char opt1, opt2, metal;
double dens;

printf("Please enter the menu option corresponding \nto the shape of the machined part you wish to build.\n");
printf("A - Cylinder \nB - Rectangle \nC - Cone\nEnter option: ");
scanf("%c", &opt1);

printf("Please enter the menu option corresponding \nto the metal you wish to build the part from: ");
printf("\n1 - Aluminium \n2 - Copper \n3 - Steel\nEnter option: ");
scanf("%c",&opt2);


int check=0;

switch(opt2)
{
    case '1':
    {
        dens=al;
        metal=itoa("Aluminium");
        check=1;
        break;
        }
    case '2':
    {
        dens=cu;
        metal=itoa("Copper");
        check=1;
        break;
        }
    case '3':
    {
        dens=st;
        metal=itoa("Steel");
        check=1;
        break;
        }
    default:
    {
        printf("Invalid option selected.");
        break;
    }
}


if(check==1)
{

switch(opt1)
{
    case 'A':
    {
        double r,h, vol, weight;

        printf("Please enter the radius of the cylinder in cm: ");
        scanf("%lf",&r);
        printf("Please enter the height of the cylinder in cm: ");
        scanf("%lf", &h);

        vol=pi*pow(r,2)*h;
        weight=vol*dens;

        printf("********************\n  MACHINE PART \n  Shape: Cylinder \n  Metal: %c\n    Metal density: %lf\n    Volume: %lf\n    Weight: %lf\n********************\n", metal, dens, vol, weight);

        break;
    }
    case 'B':
    {
        double l,b,h, vol, weight;

        printf("Please enter the length of the rectangle in cm: ");
        scanf("%lf",&l);
        printf("Please enter the breadth of the rectangle in cm: ");
        scanf("%lf",&b);
        printf("Please enter the height of the rectangle in cm: ");
        scanf("%lf", &h);

        vol=l*b*h;
        weight=vol*dens;

        printf("********************\n  MACHINE PART \n  Shape: Rectangle \n  Metal: %c\n    Metal density: %lf\n    Volume: %lf\n    Weight: %lf\n********************\n", metal, dens, vol, weight);

        break;
    }
    case 'C':
    {
        double r,h, vol, weight;

        printf("Please enter the radius of the cone in cm: ");
        scanf("%lf",&r);
        printf("Please enter the height of the cone in cm: ");
        scanf("%lf", &h);

        vol=(1.0/3.0)*pi*pow(r,2)*h;
        weight=vol*dens;

        printf("********************\n  MACHINE PART \n  Shape: Cone \n  Metal: %c\n    Metal density: %lf\n    Volume: %lf\n    Weight: %lf\n********************\n", metal, dens, vol, weight);

        break;
    }
    default:
    {
        printf("Invalid option selected.");
        break;
    }
}
}
}

---

its atoi and NOT itoa :)

a way to remember: ascii TO integer

Hey thanks :) still not running properly tho

about the atoi - itoa function, i was wondering if maybe my datatype is wrong all together...is using a char to store what in Java is a string acceptable?

Code:

---

scanf("%c", &opt1);

---

That scans in your character but leaves the newline character in your buffer, which is gladly accepted as a character for the next input. Cprogramming.com FAQ > How do I get a number from the user (C)

It only runs ONE TIME. You need to add a third option of telling it when to quit and then use a WHILE statement or a DO-WHILE until that third option is used. You can put that third option in the first switch(opt2), like a 'Q' or 'q'. It would work the same in Java also.

sorry im confused...i understand y the scanf isnt working - the whole buffer thing. but im not sure how to fix it...

@kcpilot what only runs one time and what must quit?