checking an array for a value

Hello. I have a small piece of code here, allowing the user to enter 16 characters from 'a' to
'z'. What would be the best way to make the code check if the character hasn't been entered before (is in the array) ?

Code:

---

for (i=0; i<16; i++){
printf("%d: ",i+1);
while(((virsotne[i]=getch())<97) || (virsotne[i]>122));
printf("%c\n",virsotne[i],virsotne[i]);
}

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You will have to cycle thru the array and compare each number. Write a function to make repeating this easier and pass the array in:

Code:

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int checkArray (char *array, char ch) {
      int i, len = strlen(array);
      for (i=0;i<len;i++) {
          if (array[i] == ch) return 1;
      }
      return 0;
}

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Actually I knew the algorithm to use for this array check, but the problem was to include it in the while statement. Somehow I forgot about the possibility of a function there - now everything works, thanks MK27 ;)