Code question..

Hi i have made this simple code:

Code:

---

#include <iostream>
#include <stdlib.h>
#include <iomanip>

using namespace std;

int main(int argc, char *argv[])
{

int MyArray[10];


for(int i=0;i<10;i++){
    cout<<setw(7)<<"MyArray["<<i<<"] = "<<i<<endl;
    cout<<setw(16)<<"Value for Element "<<i<<"  = "<<1+rand()%10<<endl;
 

}   
  system("PAUSE");       
  return 0;
}

---

my problems are:

1. i want to make an Histogram, for the random value..
for example if i have a value 10, i want to print 10 asterisks..

2. how to set the output to this:

MyArray[] Value Histogram
0----------> 4 ----> ** **
1----------> 2 ----> **


Thanks in advance..

use a nested loop, two loops deep. The outer loop will initialize a variable to control how many times through the inner loop you will go. the inner loop will output a single character (asterix) each time through the loop. You can put a space between each group of two character if you wish. When output for inner loop completed go to the next line before starting next time through inner loop.

>1. i want to make an Histogram, for the random value..
>for example if i have a value 10, i want to print 10 asterisks..

Another idea is to make a string filled with *'s. Then use the substr() function to display a certain number of *'s based on the value in MyArray[i].

Quote:

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Originally Posted by swoopy

>1. i want to make an Histogram, for the random value..
>for example if i have a value 10, i want to print 10 asterisks..

Another idea is to make a string filled with *'s. Then use the substr() function to display a certain number of *'s based on the value in MyArray[i].

---

This method is limiting. What if I only have 20 '*' in my string and the value is 21?

the number of * in the string could be determined based on user input.


int size;
cout << "enter # of * to use as max per line" << endl;
cin >> size;
string str;
for(int i = 0; i < size; ++i)
str += "*";

or better yet:

string str(size, '*');

should work.

The easy way (a modification of what I think elad is saying):

Code:

---

#include <string>
#include <iostream>
using namespace std;
...
int MyArray[10];
...
for( int j = 0; j < 10; ++j )
    cout << string(MyArray[j],'*') << endl;

---

This simply uses the string constructor to automatically generate a string of '*' characters of length MyArray[j] for each element of the array.

for( int j = 0; j < 10; ++j )
cout << string(MyArray[j],'*') << endl;

well done.

Quote:

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> cout << string(MyArray[j],'*') << endl;

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Awesome, I like the looks of that!