I'm confused about "parse error"

I am writing a program that converts celsius to farenhiet and vice versa. I made two function's that do the converting for me so that all I have to do is call them like this:
<code>
(line 29) result = farenhiet_(float cels);
</code>
where "result" is a defined variable of type float, I call the other function this way as well in line 36. when I compile The program though I get the error: parse error before ')'. I have tried everything, but to be honest I don't understand what parse or parsing is, let alone a parse error. I'll insert the function definition.
<code>
//funtion #1
float farenhiet_(float cels)
{
float result;
result = (1.8 * cels) + 32;
return result;
</code>
If you need the whole source I'll cut and paste that as well just let me know. Any help would be very appreciated. Thanks

OK, post the code, execept use the code tags with [], not <>

Perhaps you have to use 32.0 instead of 32, since you use floats.
Not sure what a parse error is though...

sorry about the first post. w/ wrong code tags.

Code:

---

29.    result = farenhiet_( float cels );

---

This is the definition:

Code:

---

//funtion #1
  float farenhiet_(float cels)
  {
  float result;
  result = (1.8 * cels) + 32;
  return result;

---

Post all your code and I'm sure that's a typo where you missed the '}' at the end of your function. Oh wait, no it's not. Probably your problem

Code:

---

#include <iostream>
#include <stdlib.h>
//function prototypes
float celsius_(float faren);
float farenhiet_(float cels);
void show_menu();
int main(int argc, char *argv[])
{
 //declared variables
 float celsius_, farenhiet_, result, result1;
 celsius_ = 0.0;
 farenhiet_ = 0.0;
 //declared variables
 int answer_, pass_;
 answer_ = 0;
 pass_ = 0;
 
 cout << "This program converts celsius to farenhiet and vice versa. " << endl;
 cout << "Would you like to continue? 0 for No, 1 for Yes."<<endl;
 cin>>pass_;
 while (pass_ > 0)//beginning of while loop
 {                  //with if statements inside
 show_menu();      //first function called 
 cin>>answer_;
    if (answer_ == 1)
 {
    cout << "Enter the degree celsius that you want to convert to farenhiet: "<<endl;
    cin>>celsius_;
    result = farenhiet_( float cels );
    cout << "The answer is: " << result << endl;
 } 
    else if (answer_ == 2)
 {
    cout << "Enter the degree farenhiet that you want to convert to celsius: "<<endl;
    cin>>farenhiet_;
    result1 = celsius_( float faren );
    cout << "The result is: " << result1 << endl;
    }
  }   
  system("PAUSE");       
  return 0;
  }
 
  //funtion #1
  float farenhiet_(float cels)
  {
  float result;
  result = (1.8 * cels) + 32;
  return result;
  }
  //funtion #2
  float celsius_(float faren)
  {
  float result;
  result = .55 * (faren - 32);
  return result;
  }
  //Function #3
  void show_menu()
  {
  cout << "Enter a number."<<endl;
  cout << "1. Celsius to Farenhiet."<<endl;
  cout << "2. Farenhiet to Celsius."<<endl;
  }

---

I tried taking the "float" out of the call...ended up with more errors.

Code:

---

float celsius_(float faren)
  {
  float result;
  result = .55 * (faren - 32);
  return result;
  }

---

Try using:

Code:

---

result = 0.55*(faren-32);

---

The reason for the underscores is because I was changing the code around so much that it began getting very confusing trying to follow the variables around so I put underscores after the variables in the main and in my function prototypes. It may seem weird to you but it was less confusing to me.

Well you can still change it's name. how about celsius1_

I changed the varibles: celsius_ , farenhiet_ to celsius, farenhiet.
deleted the underscores and followed them in the main and corrected them too. compiled and the parse error remained..
Do you think it might have to do with my Compiler it's a Bloodshed C++ compiler. a free one.

I changed the variable names like you said and put 0.55*(faren -32).

Code:

---

#include <iostream>
#include <stdlib.h>
//function prototypes
float celsius1(float faren);
float farenhiet1(float cels);
void show_menu();
int main(int argc, char *argv[])
{
 //declared variables
 float celsius, farenhiet, result, result1;
 celsius = 0.0;
 farenhiet = 0.0;
 //declared variables
 int answer, pass;
 answer = 0;
 pass = 0;
 
 cout << "This program converts celsius to farenhiet and vice versa. " << endl;
 cout << "Would you like to continue? 0 for No, 1 for Yes."<<endl;
 cin>>pass;
 while (pass > 0)//beginning of while loop
 {                  //with if statements inside
 show_menu();      //first function called 
 cin>>answer;
    if (answer == 1)
 {
    cout << "Enter the degree celsius that you want to convert to farenhiet: "<<endl;
    cin>>celsius;
    result = farenhiet1( float cels );
    cout << "The answer is: " << result << endl;
 } 
    else if (answer == 2)
 {
    cout << "Enter the degree farenhiet that you want to convert to celsius: "<<endl;
    cin>>farenhiet;
    result1 = celsius1( float faren );
    cout << "The result is: " << result1 << endl;
    }
  }   
  system("PAUSE");       
  return 0;
  }
 
  //funtion #1
  float farenhiet1(float cels)
  {
  float result;
  result = (1.8 * cels) + 32;
  return result;
  }
  //funtion #2
  float celsius1(float faren)
  {
  float result;
  result = 0.55 * (faren - 32);
  return result;
  }
  //Function #3
  void show_menu()
  {
  cout << "Enter a number."<<endl;
  cout << "1. Celsius to Farenhiet."<<endl;
  cout << "2. Farenhiet to Celsius."<<endl;
  }

---

Quote:

---

Originally posted by Chizzlah
Do you think it might have to do with my Compiler.

---

no