cube root

how do you find this? i tried this:

Code:

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        fyards = (area ^ (1/3)); //cube root

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but i came up with this:

63 C:\Dev-Cpp\program2.cpp invalid operands of types `float' and `int' to binary `operator^'

help?

The power function is in the library <cmath>
And it goes like this:

Code:

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variable = pow(x,y);
//Where x is what you want and y is the power
double temp = pow(8,(1.0/3.0) ); //Will get you 2

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Alternative, if area is guaranteed to be greater than zero, would be;

Code:

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  fyards = exp(log(area)/3.0);

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Quote:

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Originally Posted by grumpy

Alternative, if area is guaranteed to be greater than zero, would be;

Code:

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  fyards = exp(log(area)/3.0);

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This is actually what the pow function does.

Mathematically it is equivalent. As to it being what the pow() function actually does: that's implementation dependent. I suggest pow() will also do a few other things, otherwise it wouldn't work if the first argument is negative.

^ is the XOR operator by the way...

Quote:

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Originally Posted by arjunajay

^ is the XOR operator by the way...

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Yup.

But the way the question was asked he was using x^y as a notation for "x raised to the power of y".