Input student grades

I was given a task to create a program that:



1. convert to grade
2. calculate number of every grade like if there's inputted 5 times a score that equal to A then A = 5
3. calculate average of score (using function)
4. print stars depending of every grade A = 5 =*****, b = 2 = **


I couldn't figure out the number 2, i think there's a small problem with my code

Code:

---

#include <stdio.h>
#include "func.h"


int main()
{
        int score, avg, count, total, student, aCount, bCount, cCount, dCount, eCount, k, skor, sick, haz;
        total = 0;
        student = 1;
        aCount = 0;
        bCount = 0;
        cCount = 0;
        dCount = 0;
        eCount = 0;
        char grade;


        while (student <=10){
        printf("Please enter the score: ");
        scanf("%d", &score);
        sick = score;
        haz = counting(sick, aCount, bCount, cCount, dCount, eCount);
        student++;
        total = total + score;
        grade = score2grade(score);
        printf("Score = %d => grade=%c\n", score, grade);
        }
        avg = average(avg, total);
        printf("The Average is %d\n", avg);
        printf("A: %d = ", aCount);
                for(k=1; k<=aCount;k++){
                        printf("%s", "*");}
                        printf("\n");
        printf("B: %d = ", bCount);
                for(k=1; k<=bCount;k++){
                        printf("%s", "*");}
                        printf("\n");
        printf("C: %d = ", cCount);
                for(k=1; k<=cCount;k++){
                        printf("%s", "*");}
                        printf("\n");
        printf("D: %d = ", dCount);
                for(k=1; k<=dCount;k++){
                        printf("%s", "*");}
                        printf("\n");
        printf("E: %d = ", eCount);
                for(k=1; k<=eCount;k++){
                        printf("%s", "*");}
                        printf("\n");
        return 0;
}

---

and the function

Code:

---

#include <stdio.h>


int counting(int sick, int aCount, int bCount, int cCount, int dCount, int eCount)
{
        if (sick >= 85) {aCount++;}
                else if(sick >= 70) {bCount++;}
                        else if(sick >= 60) {cCount++;}
                                else if(sick >= 55) {dCount++;}
                                        else {eCount++;}
}


char score2grade(int score)
{
        if (score >=85) return 'A';
                else if(score >=70) return 'B';
                        else if(score >= 60) return 'C';
                                else if(score >= 55) return 'D';
                                        else return 'E';
}


int average(int avg, int total)
{
        avg = total/10;
}

---

If you can help me a little I'll appreciate it.
Thanks in advance.

Have you learned about pointers or pass by address?

Tim S.

Quote:

---

Originally Posted by stahta01

Have you learned about pointers or pass by address?

Tim S.

---

No i haven't

Quote:

---

Originally Posted by andre2539

No i haven't

---

Then, you need to know that functions can only return one value at most per function.
I suggest you reread the book about using functions.

Tim S.

Code:

---

int counting(int sick, int aCount, int bCount, int cCount, int dCount, int eCount)
{
        if (sick >= 85) {aCount++;}
                else if(sick >= 70) {bCount++;}
                        else if(sick >= 60) {cCount++;}
                                else if(sick >= 55) {dCount++;}
                                        else {eCount++;}
}

---

The above will not do what you want.

Code:

---

void counting(int sick)
{
        if (sick >= 85) {aCount++;}
                else if(sick >= 70) {bCount++;}
                        else if(sick >= 60) {cCount++;}
                                else if(sick >= 55) {dCount++;}
                                        else {eCount++;}
}

---

The above likely will do what you want; but, it is considered poor programming to use Global variables most of the time. But, this might be a time to use them because you do not yet know pass by value.

Tim S.