Do while problem

Could you please help why my program goes through do while loop just once, although the condition is true.
//Program is getting numbers from user and realize whether they are correct numbers for triangle side or not and if tey find out the area//


#include<stdio.h>
#include<math.h>
double TraingleArea();
int main(void)
{
int Firstside,Secondside,Thirdside;
char Answer;
do
{
printf("Enter your Triangle's side \n");
scanf("%d %d %d", &Firstside, &Secondside, &Thirdside);
if(Firstside<=0 || Secondside<=0 || Thirdside<=0)
printf("Sides of traingle are positive,please enter three positive integer numbers.");
else
{
if(Firstside+Secondside<=Thirdside || Secondside+Thirdside<=Firstside ||Firstside+Thirdside<=Secondside)
printf("They are not valid numbers for sides of traingle.");
else
{
if(Firstside==Secondside && Secondside==Thirdside)

printf("The tringle is Equilateral\t Its area is equal to %f \n",TraingleArea(Firstside,Secondside,Thirdside) );

else if(Firstside==Secondside || Firstside==Thirdside || Secondside==Thirdside)

printf("The triangle is Isosceles\t Its area is equal to %f \n",TraingleArea(Firstside,Secondside,Thirdside) );

else
printf("The triangle is Scalene\t Its area is equal to %f \n",TraingleArea(Firstside,Secondside,Thirdside) );
}

}
printf("Would you like to continue? Y/N\n");
scanf("%c",&Answer);
}while(Answer=='Y');

}

double TraingleArea(unsigned Firstside,unsigned Secondside, unsigned Thirdside)
{
double halfPerimeter=(double)(Firstside+Secondside+Thirds ide)/2;
double Area;
Area=sqrt(halfPerimeter*(halfPerimeter-Firstside)*(halfPerimeter-Secondside)*(halfPerimeter-Thirdside));
return Area;
}

Does your user have their caps lock turned on?

Code:

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}while(Answer=='Y');

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All this stuff is case sensitive... Y is not the same as y

Please read the forum guidelines and code posting rules. Please edit your post to use code tags and proper indentation, so people can actually read your code and see what it's doing.

You said main would return an int, so please make it do so (put a return 0 at the end of it). Read this to see why it matters.
Also, you need to flush the input buffer. Read this FAQ article.
You should also allow a lower case 'y' to continue.

Quote:

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Originally Posted by anduril462

You should also allow a lower case 'y' to continue.

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Evreything you said... except he should be testing for both upper and lower case.

Alternatively, he could do:

Code:

---

#include <ctype.h>

(tolower(Answer) == 'y')

---

Thanks everybody.Is there any easier way to flush the buffer?
(my college professor said use either getcha(); or %*c . but none of these are working .)

Easier than what? You want it to read your mind and magically flush? Did you read the FAQ on it. The solution is little more than 1 line, how much simpler do you want it?

Code:

---

void flush_input(void)
{
    int c;
    while ((c = getchar()) != '\n' && c != EOF)
        ;
}

---

Then just call flush_input() wherever appropriate.

Code:

---

scanf("%d %d %d", &Firstside, &Secondside, &Thirdside);

//add this:
getchar();

---

This is not as robust as the one that Anduril has posted, above. It works fine (don't forget the 'r'), but it has the limit of pulling only one char off the input buffer. That's usually enough (one per scanf(), is normal), but not always. User's are pretty clever about making good input, turn bad! :D

When the above is working properly, you will NOT notice it - execution of the program will continue, and not pause. ONLY time it will pause, is if the input buffer is already empty, and that is not the normal case after a scanf().

I have tried to use the %*c format to remove the newline char, but it failed. getchar() works, however.