stdin !

Hi,
I'm reading from a text file in my code(It's only 10 different words in that). The code should random a word from the text. how do I do that?
Can I somehow turn the text into an array of strings?so that I can random the index of the array ? Or is this impossible ?!

If you're reading from a file, what does that have to do with stdin?

Google rand() and srand().

You can also check out strtok().

Sorry for the wrong title, I can not change it now ! I meant exactly the opposite! :D
anyway...
I know how to use random() or srandom(). My problem is , how to turn the words in the file to strings?
I've been searching about it in the internet but I didn't get an answer that I could understand. It's explained in a high-level-programming language I guess!
I tried this but ain't working.

Code:

---

int main(){
FILE* sep;
 int ch,i;
 char flt[8];
sep=fopen("hangman.dat","r");
 for(i=0;i<8;i++){
  ch=getc(sep);
  if(ch=='\n')
      flt[i]=ch;
 }
 fclose(sep);
 return 0;
}

---

I'll really appreciate it if someone gives me some hints on it.

Google for fgets().

ok, I'm using fgets now in the code, and I try to save each line (only one word in each line) as an element in the array "flt" . but all elements of the array become the last line/word! I mean they all have one and the same string i.e. the last word in the file.
flt[0]=organisation
flt[1]=organisation
.
.
.
flt[7]=organisation !!!!

Code:

---

int main(){
  char ch[20];
  int i,j;
  char* flt[8];
FILE *sep;
sep=fopen("hangman.dat","r");
 for(i=0;i<2;i++){
  fgets(ch,20,sep);
  flt[i]=ch;
 
 }
 for(j=0;j<2;j++){
  printf("%s",flt[j]);
 }

 fclose(sep);

 
 return 0;
}

---

Yes, you are just storing the address of ch in your flt array. As you read new data, the content of ch changes. You need to either:
- Have a 2D array
- Allocate memory for your strings as you read them in, and copy the contents of ch into the allocated memory.

[If you print the VALUE of flt[0..7], e.g printf("%p", flt[i]), you will see that all strings have the same address, and thus are actually just the same string multiple times].
--
Mats

Quote:

---

Originally Posted by matsp

Yes, you are just storing the address of ch in your flt array. As you read new data, the content of ch changes. You need to either:
- Have a 2D array
- Allocate memory for your strings as you read them in, and copy the contents of ch into the allocated memory.

[If you print the VALUE of flt[0..7], e.g printf("%p", flt[i]), you will see that all strings have the same address, and thus are actually just the same string multiple times].
--
Mats

---

tnx for d reply, but we haven't reached that far i C yet. I mean we haven't learned abt 2D array or allocated memory.
So i'm wondering if there is another easier way to do this.

Quote:

---

Originally Posted by sifeet

tnx for d reply, but we haven't reached that far i C yet. I mean we haven't learned abt 2D array or allocated memory.
So i'm wondering if there is another easier way to do this.

---

No, there isn't. You'll just have to learn about 2D arrays [that's the less complex option].

--
Mats

Code:

---

int main(){
  char ch[20];
  int i,j;
  char* flt[9][20];
  FILE *sep;
  sep=fopen("hangman.dat","r");
  for(i=0;i<9;i++){
    for(j=0;j<20;j++){
      flt[i][j]= fgets(ch,20,sep);
    }
  }
 

  fclose(sep);
 
 
  return 0;
}

---

still not working :-S

I wouldn't expect that to work...

1. You have a 2D array of pointers to char, you need a 2D array of char.
2. You could then read straight into your array with

Code:

---

  for(i=0;i<9;i++){
      fgets(flt[i],20,sep);

---

--
Mats

Quote:

---

Originally Posted by matsp

I wouldn't expect that to work...

1. You have a 2D array of pointers to char, you need a 2D array of char.
2. You could then read straight into your array with

Code:

---

  for(i=0;i<9;i++){
      fgets(flt[i],20,sep);

---

--
Mats

---

It's working now =D thanks a lot! =)