string problem, someone please!!

firstly i want to thank for someone who reply me

my problem is

Code:

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// Join solutions together as string, and brek up after two numbers.
   
    stringstream numbers;

    // Insert integer into stringstream
    numbers <<numLowerCaseLetter(name)<<sumAscii(name)<<lastValue<<counter<<sum;

    // Convert stringstream into string
    string str = numbers.str();
   
    for(int i = 0; str[i]; i=i+2)
    {
        cout<<str.substr(i,2)<<" "; 
    }

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EXPLANATION OF MY PROBLEM::

output is: 55 20 11 84 18

for the code above, it is to split strings after 2 numbers.
when i enter str[1] it displays only 5. how can i do to make it display 55 when i asked for str[0]?

Quote:

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how can i do to make it display 55 when i asked for str[0]?

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You can't. str[0] is a char type, which means it only stores one character.

Quote:

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output is: 55 20 11 84 18

for the code above, it is to split strings after 2 numbers.

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It appears to have done a pretty good job!

>for the code above, it is to split strings after 2 numbers.
Your code should work, except:

Code:

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    for(int i = 0; str[i]; i=i+2)
    {
        cout<<str.substr(i,2)<<" "; 
    }

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Instead this should be:

Code:

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    for(int i = 0; i<str.length(); i=i+2)
    {
        cout<<str.substr(i,2)<<" "; 
    }
    cout << endl;

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Or maybe:

Code:

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    for(int i = 0; i+1<str.length(); i=i+2)
    {
        cout<<str.substr(i,2)<<" "; 
    }
    cout << endl;

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thanks guyz but tat is not wat my problem is .. thnx all of you ..

Code:

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#include <iostream>
#include <sstream>
#include <string>
using namespace std;

int main(void)
{
  stringstream text("55 20 11 84 18");
  string before, after;
  for (int i = 0; i < 2; ++i)
  {
      text >> after;
      before += after + ' ';
  }
  getline(text, after);
  cout << "before: " << before << '\n';
  cout << "after:  " << after  << '\n';
  return 0;
}

/* my output
before: 55 20
after:  11 84 18
*/

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