Confused with double pointers

I have been trying for hours to create a specific prototype program that determines a pascal's triangle for a give number of rows. However, prototype must have the return type of int**. I just recently learnt about pointers and I would really appreciate it if anyone could give me a hint as to why my attempt of the function doesn't work.
As well, i am not sure how I can check if my return value actually points to the pascal triangle.

Code:

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#include <stdio.h>
#include <stdlib.h>


int **getPascalTriangle(int n)
{
    int i, j, value;
    int *c;
    int ** pp;
    int k, gap;


    c=(int*)malloc(n*sizeof(int));


    printf("\n");
    gap=n;


    for(i=0;i<=n-1;i++)
    {  value=1;


        for(k=gap;k>=0;k--)
            printf(" ");
            gap--;


            for(j=0;j<=i;j++)
                {
                c=&value;
                value=(*c*(i-j)/(j+1));
                }


        printf("\n");
}
    *pp=c;
    return pp;
}


 int main(void)
{
    int n;


    printf("Please enter value for number of rows in PAscal's triangle:");
    scanf("%d",&n);


    getPascalTriangle(n);




    return 0;
}

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You don't seem to have allocated space for the dynamic 2D array. You did allocate space for a dynamic 1D array, but this assignment doesn't work as there was no space allocated for the dynamic 2D array:

Code:

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*pp=c;

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even if you did allocate the space, it still wouldn't do what you want since it only copies a pointer. Furthermore, you wrote:

Code:

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c=&value;

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which overwrites C, thus resulting in a memory leak since c pointed to what was returned by malloc. Speaking of that, you should not be printing anything in getPascalTriangle. Rather, call it in the main function, then use its return value to print the Pascal's triangle. Finally, free the memory allocated.

By the way, although you do appear to have made some effort to indent your program properly, it still needs more work in that area.