how do you declare a single dimentional array over several lines

obviously you can initialize a single array like this

Code:

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int myarray[5] = { 1, 2, 3, 4, 5 };

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but if you had a big array that needed to be initialized at declaration time how do you span multiple likes rather than one long string

Everywhere you have a white space, you can have a newline.

Code:

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int myarray[5] = {
  1, 2,
  3, 4,
  5
};

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You can do the same with strings also.

Code:

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char text[] = "The quick brown fox "
              "jumps, over the lazy dog!";

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thanks they are about the only combinations i didn't try

Are you trying to read the cipher data into an array? If so, instead of hard-coding it into your program text, you can read it directly from the file like this:

Code:

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#include <stdio.h>
#include <stdlib.h>
 
#define INPUTFILE "cipher.txt"
 
int get_text(char *text) {
    FILE *file = fopen(INPUTFILE, "r");
    if (!file) {
        perror(INPUTFILE);
        exit(EXIT_FAILURE);
    }
 
    int len = 0;
    // The %*c reads and ignores the comma after the integer.
    for (int ch; fscanf( file, "%d%*c", &ch ) == 1; )
        text[len++] = ch;
    fclose(file);
 
    return len;
}
 
int main() {
    char text[1500]; // Input has 1455 chars
    int len = get_text(text);
    printf("%d\n", len); // should print 1455
    return 0;
}

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thanks you read my mind i was getting to the point of cut and paste and having it as a fixed array