trying to learn strlen

Hi,

trying to learn strlen, and after typing out an example out of a book.

For some reason, it doesn't work. =(

I double checked that there is no typing/syntax errors. It's in german, but the code is in English =)

Can anyone give me a clue as to why this doesn't compile?

Thanks!

Code:

---

//* noch ein beispiel: strlen.c *//

#include <stdio.h>
#include <string.h>

int main (void)
{
    char string [100] = "So lang ist dieser String:";
    printf ("So gross ist das char-Array: %d\n", sizeof (string));
    printf ("%s %d\n", string, strlen (string));
}

---

Its is compiling, what kind of error you are facing?

strange. I get the following error.

Code:

---

strlen.c: In function ‘main’:
strlen.c:9: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘long unsigned int’
strlen.c:10: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘size_t’

---

I found another simple example online, and it also doesn't compile.

This is my compiler version:
gcc version 4.4.3 (Ubuntu 4.4.3-4ubuntu5)
maybe that has something to do with it.

Type specifier for `size_t` type, which is what `strlen()` and `sizeof` return, is `%zu`. Also, it's common to not put a space between function name and respective parenthesis in a function call; that's usually used for loops.

It does compile... those are warnings, not errors. Errors would result in no executable being produced. Warnings will result in an executable being produced.

[QUOTE=jalisco;1088000]strange. I get the following error.

Code:

---

strlen.c: In function ‘main’:
strlen.c:9: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘long unsigned int’
strlen.c:10: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘size_t’

---

The above mentioned are warnings not errors, it will not halt your compil

Ah! thanks for the replies.