converting string into array

im trying to convert a string into an array


cint1 is "1abcd" (char)

Code:

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    char archar[] = {cint1};


    printf("%s", archar[0]);

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the entire code is:

Code:

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    int int1;


    char char1[30] = "a";
    char char2[30] = "b";
    char char3[30] = "c";
    char char4[30] = "d";


    char cint1[40] = "";
    int1 = 1;




    itoa(int1,cint1,10);




    strcat(char1,char2);
    strcat(char1,char3);
    strcat(char1,char4);


    strcat(cint1,char1);




    printf("%s",cint1);


    char archar[] = {cint1};


    printf("%s", archar[0]);

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This is so wrong! You really need to study a good up to date book on the C Programming Language rather than try to hack your way trying to use a non-standard function in such a ridiculous way!

When I am near my computer later I will explain further.

ive figured it out

Code:

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char my_string[] = {""};

strcpy (cint2,my_string);

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Quote:

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Originally Posted by WaterSerpentM

ive figured it out

Code:

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char my_string[] = {""};

strcpy (cint2,my_string);

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No, you didn't! Will respond later.

Quote:

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Originally Posted by rstanley

No, you didn't! Will respond later.

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ye you're right, it outputs a blank line