Segmentation faults

Hi all,

Why the following code gives segmentation fault ????

Code:

---

#include<stdio.h>

int main()
{
        char *p="hello";
        printf("%s",p);
        printf("\n%c",*p);
        p++;
        *p='g';
        printf("\n%s",p);
        return 0;
}

---

You are trying to modify a string literal. You shouldn't try to do that.

Code:

---

char p[] ="hello";

---

You can modify six characters there. Five if you want it to remain a string.


Quzah.

This thread goes a little deeper into why you can't do that: http://cboard.cprogramming.com/c-pro...als-store.html

Quote:

---

Originally Posted by quzah

You are trying to modify a string literal. You shouldn't try to do that.

Code:

---

char p[] ="hello";

---

You can modify six characters there. Five if you want it to remain a string.


Quzah.

---

This is also creating problems....

Code:

---

#include<stdio.h>

int main()
{
        char p[]="harpreet";
        printf("%s",p);
        printf("\n%c",*p);
        p++;
        *p='g';
        printf("\n%s",p);
        return 0;
}

---

The above code produces the following error...

Code:

---

Test.c: In function ‘main’:
Test.c:8: error: lvalue required as increment operand

---

What is the reason for this ???
please help....

Regards
C_Enthuaist

The reason is that you cannot increment an array. What you can do is to get a pointer to point to the first element of the array, and then increment that pointer.