Pointers help please(using pointers to copy a string)

question A: in the while loop we have,"*pB++ = *pA++; " to copy the contents of strB to strB, why is the entire string copied because *ptrA++ insures that it starts from the second character in the string does it not?? please explain this.questionB:the size of strB is obviously to small to accept the contents of strA yet it does, ? can some one please explain why

Code:

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#include char strA[80] = "A string to be used for demonstration purposes";char strB[1];int main(void){          char *pA;              // a pointer to type character          char *pB;              // another pointer to type character          puts(strA);            // show string A          pA = strA;            // point pA at string A */          puts(pA);              // show what pA is pointing to */          pB = strB;            // point pB at string B          putchar('\n');          while(*pA != '\0') {      //copies strA tp strB                *pB++ = *pA++;          }        *pB = '\0';                  // adds the nul terminator to strB          puts(strB);          return 0;}

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'*ptrA++ insures that it starts from the second character in the string does it not?' no it does not. the postfix ++ increments the pointer AFTER the assignment. but thats not your problem. you are just overwriting the memory that follows wherever strB is located. C doesn't protect from overwrites like that. you can happily corrupt memory all you want. you have to deal with the length of the destination string yourself, with a counter or something. look at the definitions of 'strcpy' and 'strncpy' to see an example.