Need help w/ program!

I desperately need help on program. I'm not sure on what to do. I don't even know where to begin actually. But this program I'm trying to write is to get 3 numbers from main and to call 1 function to determine the maximum and minumum numbers. No global variables. And use call-by-reference. I'd appreciate any help I can get. Even an example or something would be great. Thanks!

Code:

---

int max(int a, int b, int c) {
int x=a;
if (b>x) x=b;
if (c>x) x=c;
return x;
}

---

min works the same way. there's probably a more cryptic and smaller way to do this, but this will work.

What about the part w/ the function? And how will it work? Sorry, i'm a newbie. Just trying to learn. Any more suggestions?

do you need to get them as command line arguments? the function could look like this:

void minandmax( int& min, int& max, int array[], int arraySize )
{
for( int i = 0; i < arraysize; i++ )
{
min = max = array[ 0 ];

if( array[ i ] > max )
{
max = array[ i ];
}

if( array[ i ] < min )
{
min = array[ i ]
}
}

at the end of this, min will be the minimum and max the maximum values. This is not the easiest (and probbaly not the best!) way to do it though

sorry, missed a } at the end as well

int max(int a, int b, int c)
{return (a>b?b:a)>c?c: (a>b?b:a);}

Isn't it pretty?:D

>to call 1 function to determine the maximum and minumum
>numbers.

I guess unregistered wanted a function which determins the maximum AND the minimum value and not two seperate functions for determining maximum and minimum.

Code:

---

int main (void)
{
    int a, b, c, min, max;

    // give a, b and c a value

    minmax (a, b, c, &min, &max);

    return 1;
}

void minmax (int a, int b, int c, int *min, int *max)
{   
    *min = a;
    if (b < *min) *min = b;
    if (c < *min) *min = c;
   
    *max = a;
    if (b > *max)*max = b;
    if (c > *max)*max = c;
}

---

Yes, Shiro. Thanks! I really appreciate all of your help. =)

Hi! It's me again. Here's my program. It runs fine but I'm getting the wrong minimum and maximum answers. Can anyone tell me why? And why I have 2 warnings? It's probably why my answers are wrong. I tried to look up the warnings in the Help Index, but it keeps freezing on my crappy computer. Hehe.
------------------------------------------------------------------------------------
warning C4700: local variable 'min' used without having been initialized
warning C4700: local variable 'max' used without having been initialized
------------------------------------------------------------------------------------
#include <iostream.h>
#include <iomanip.h>

void minmax_fn ();

int main ()

{
int a;
int b;
int c;
int min;
int max;

cout<<"\n Enter first number: ";
cin>> a;
cout<<"\n Enter second number: ";
cin>> b;
cout<<"\n Enter third number: ";
cin>> c;

cout<<"\n The minimum value is: "<< min;
cout<<"\n The maximum value is: "<< max;

return 0;

}

minmax_fn (int a, int b, int c)

{

int min = a;
if (b < min)
min = b;

if (c < min)
min = c;

return min;

int max = a;
if (b > max)
max = b;

if (c > max)
max = c;

return max;

}

didn't he say he needed to use passing by refrence so shouldn't it be somthing like this

void minmax (int a, int b, int c, int & min, int & max)

using pointers to access the original variables is still passing by value

Yeah, I went back to fix it. I just figured out why I had the warnings! durh~! But what do i set min and max equal to? I've tried the formulas.. tested it.. thought it worked.. but it didn't.

min= ?
max=?

Anyone out there? I just need the formula(s) to initialize min and max. Please help!

cout<<"\n Enter first number: ";
cin>> a;
cout<<"\n Enter second number: ";
cin>> b;
cout<<"\n Enter third number: ";
cin>> c;

min= //initialization
max= //initialization

cout<<"\n The minimum value is: "<<min;
cout<<"\n The maximum value is: "<<max;

Nevermind!!!!!! I got it! I feel kind dumb, but it didn't work b/c I had the formulas on one line. Durh! Should've known!! Perserverance is key!!!