Ok I'm stuck with a double to float error

Here's the snippet of code that I'm having problems with:

Code:

---

             

                int            customernumber;
        float        waterlevel;
        float        previouslevel;
        float        totalwater;
        float        totalbill;
        float        amountowed;


        printf("Enter customer number\n" );

        scanf( "%d" ,  &customernumber );

        printf("Enter current water level\n" );

        scanf("%f" , &waterlevel );

        printf("Enter previous water level\n" );

        scanf("%f", &previouslevel );

        totalwater = waterlevel - previouslevel;

        totalbill = 30 + (totalwater/1000  * .55);

        amountowed = totalbill;

---

I keep getting this warning "conversion from double to float, possible loss of data" for this line

totalbill = 30 + (totalwater/1000 * .55);

I dont understand what it could mean, everything is declared as float ( I, obviously, made sure of that), if anyone has any idea what's wrong with this line I would really appreciate it if ya could share it with me.
Thank you very much.

.55 by itself is a double constant.
Since the rest of the expression is float, I think it's this one which making the whole of the right hand side into a double expression.

So when you perform the assignment, the now double expression on the right is being converted to a float.

.55F is the way to define a float constant.

Or you could just add a cast:

Code:

---

totalbill = (float) (30 + (totalwater/1000 * .55));

---

[EDIT]
Or maybe declare everything as double and not as float.