sizeof returns unexpected result

Considering the following code:

Code:

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int fnParser(char *buffer,float* pOutput){
    int c = 0;
    char * pch;
    pch = strtok (buffer,",");
    pOutput[c] = atof(pch);
    while (pch != NULL)
    {
        c++;
        pch = strtok(NULL, ",");
        if(pch != NULL) pOutput[c] = atof(pch);
    }
    return sizeof(pOutput);
}

char buffer[] = "200,300,123456,1.00000,.707,.4,'.404";float *fParseData;

int iSize=fnParser(buffer,fParseData);
printf("Buffer size = %i\n",iSize);

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fnParser converts 'buffer' into a 7 member array 'pOutput' so why does sizeof(pOutput) aka iSize keep coming up 4 instead of 7?

Why would it come up with 7? Where is 7 associated with sizeof(float *)?

It's returning the size of a float pointer, which on your system is 4. If you're trying to find out how much space you allocated for it, sizeof won't work.

I had expected buffer to be broken down into 7 comma separated values, one value placed into each cell of of pOutput. When I execute the following code:

Code:

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  float *fParseData;            int iSize=fnParser(buffer,fParseData);
            printf("RECEIVED TARGET:\n");
            printf("  x: %f\n",fParseData[0]);
            printf("  y: %f\n",fParseData[1]);
            printf("  z: %f\n",fParseData[2]);
            printf("  q1: %f\n",fParseData[3]);
            printf("  q2: %f\n",fParseData[4]);
            printf("  q3: %f\n",fParseData[5]);
            printf("  q4: %f\n",fParseData[6]);
            printf("Buffer size = %i\n",iSize);
            printf("\n");

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Each cell contains the 'expected' value so I had assumed sizeof(fParseData) would be 7.

But I think I understand: sizeof(fParseData) would be 7 if:

Code:

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float fParseData[6];

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which is not what I did.
Instead I can:

Code:

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return (c);

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But is there a better way to determine how many valid (not NULL) members are being pointed to by fParseData?

If you're only using stack arrays, you can do

Code:

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float fParseData[6];
printf("%lu\n", sizeof(fParseData));

/* meaning, 6 times 4 (sizeof(float)), so it correctly returns 24 */
/* if you want elements in the array, do this: */

printf("%lu\n", sizeof(fParseData) / sizeof(float));

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If you're doing malloc()/heap arrays, and they are properly null terminated, you can write your own function to increment a copy of the pointer until the pointee is zero.

Quote:

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But is there a better way to determine how many valid (not NULL) members are being pointed to by fParseData?

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Ummm...count them as you put them in? Or am I being too logical?

> Each cell contains the 'expected' value so I had assumed sizeof(fParseData) would be 7.
sizeof operates at compile time. Since fParseData is only known to be a float * at compile time, all the compiler can do is tell you the size of a float * (4 bytes on your system).

> But I think I understand: sizeof(fParseData) would be 7 if:

Code:

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float fParseData[6];

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No, it would not be 7. There are 6 elements, so a more reasonable guess would be 6. But sizeof returns the number of bytes used for storage, not the number of elements. Thus, the above declaration has a size of 6 * sizeof(float). If a float is 4 bytes, that's 24 bytes for fParseData.

> But is there a better way to determine how many valid (not NULL) members are being pointed to by fParseData?
If you don't want to track the length in a separate variable, another way is to use a sentinel value. This is how strings work in C, there is a null character ('\0') that marks the end of the string. Just allocate one more spot than you need. Depending on what values you expect to be storing in fParseData, you may be able to use -1 or FLOAT_MIN to mark the end of the list. It's really up to you to pick an appropriate sentinel value for your application. Just remember, floating point comparisons are not exact, so you need to check for something like

Code:

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if (fParseData[i] - sentinel_value < 0.0001)  // You can change 0.0001 to any reasonable tolerance

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