How to convert a int to char?

Does anyone know a way to convert an int to a char so if I have a int with the value of 45, I could convert it to a char with the value "45", anyone?

Thanks
Chris

Use the cast operator:

#include<stdio.h>

int main(void) {
int x;
char y
scanf("%x", &x);
y = (char)x;
printf("here is the eq. character: %c\n", y);
....
return 0;
}
there are certain rules about casting only certain types can be passed to another and other that can be casted to all the others.

sorry about that sub. header files and stream functions:
printf() and scanf() for cout and cin respectively.

y = (typr) x;

with multicasting it gives the number a char value and what im tryin to do is put the actuall number from the int and put the same value from int into a char.

Thanks
Chris

Well, in case you're unaware, you can't convert int into char as the int may have more than one character.
To turn an int into a char* you can use itoa() (in stdlib.h I believe), but in MSVC it's _itoa().
You use it like so:

char buf[10];//buffer to output to
int num = 45;//source value
itoa(num,buf,10);
//10 == radix (in other words, the base ie: 2=binary, 16=hex, 8=octal)

HTH.

lol...TheGr8one signs just like me, exept I put a dash before my name

Thanks
-Chris

Also wanted to mention, itoa means "Int TO Ascii"

oops, I forgot to sign in when I posted the above message

Thanks
-Chris