Number Convert function

Write a function int convert () that reads a decimal number one character(digit) at a time, terminated by a blank, and returns the value of that number.
I am trying to write program for above

Code:

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#include <stdio.h>
int main()
{ 
int number=0;   
int digit=0; 
while(digit != ' ') 
{   
printf("Enter the digit\n");   
scanf("%d,&digit");   
number = number*10 + digit; 
} 
printf("The entered number is=%d ",number);   
return 0;
}

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The code does not exit the while condition.

Code:

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$ gcc -Wall foo.c
foo.c: In function ‘main’:
foo.c:9:9: warning: format ‘%d’ expects a matching ‘int *’ argument [-Wformat=]
    9 | scanf("%d,&digit");
      |        ~^
      |        |
      |        int *
$

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Do you see what's wrong here?

Code:

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scanf("%d,&digit");

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Compare with

Code:

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scanf("%d",&digit);

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I am really sorry how that mistake happened. I will try with the changes.

Code:

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#include <stdio.h>
int main()
{
    int number=0;
    char digit=0;
   
    while(1)
    {
    printf("Enter the digit\n");
    scanf("%c",&digit);
    getchar();
    printf("digit = %d\n", digit-'0');
    if(digit == ' ')
    {
        printf("Space entered\n");
        break;
    }
    else
    {
      number = number*10 + (digit-'0');
      printf("The entered number is = %d\n",number);
    }
   
    }
    printf("The final number is = %d ",number);
    return 0;
}

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Made a working version but little complex.
Enter the digit
3
digit = 3
The entered number is = 3
Enter the digit
5
digit = 5
The entered number is = 35
Enter the digit
8
digit = 8
The entered number is = 358
Enter the digit

digit = -16
Space entered
The final number is = 358


...Program finished with exit code 0
Press ENTER to exit console.

> if(digit == ' ')
Do this.

Before you do this
> printf("digit = %d\n", digit-'0');

or this
> number = number*10 + (digit-'0');

Code:

---

#include <stdio.h>
int main()
{
    int number=0;
    char digit=0;
   
    while(1)
    {
    printf("Enter the digit\n");
    scanf("%c",&digit);
    getchar();
    if(digit == ' ')
    {
        printf("Space entered\n");
        break;
    }
    else
    {
      number = number*10 + (digit-'0');
      printf("digit = %d\n", digit-'0');
      printf("The entered number is = %d\n",number);
    }
   
    }
    printf("The final number is = %d ",number);
    return 0;
}

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I hope this is what you mean?
Enter the digit
1
digit = 1
The entered number is = 1
Enter the digit
2
digit = 2
The entered number is = 12
Enter the digit

Space entered
The final number is = 12


...Program finished with exit code 0
Press ENTER to exit console.

Instead of stopping the loop with the break statement, why not replace "while (1)" with "while (digit != ' ')"?

Quote:

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Originally Posted by Clearner123

Write a function int convert () that reads a decimal number one character(digit) at a time, terminated by a blank, and returns the value of that number.

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I'm not seeing a function called convert that returns an int.