About overloading operators.

Can you 'create' new operators? Like a +++ which would, for example add two to the variable? I tried making a simple program to find the answer for myself. But I failed miserably; I don't know if it's because I'm overlooking something, or you simply cannot do what I'm asking.

Code:

---

#include <iostream.h>
typedef unsigned short int USHORT;

class addthis
{
public:
        addthis() { val = 0; }
        ~addthis() {}
        addthis(USHORT x) { setVal(x); }
        USHORT getVal() { return val; }
        void setVal(USHORT x) { val = x; }
        addthis operator+++ ();
        addthis operator++ ();
private:
        USHORT val;
}

addthis addthis::operator+++()
{
        val = val+2;
}

addthis addthis::operator++()
{
        val = ++val;
}

int main(void)
{
        addthis ADDTHIS(22);
        cout << ADDTHIS.getVal();
        ADDTHIS+++;
        cout << ADDTHIS.getVal();
        ADDTHIS++;
        cout << ADDTHIS.getVal();
        ADDTHIS.flush();
        cout << "ADDTHIS.getVal();
        SYSTEM("PAUSE");
        return 0;
}

---

I got numerous errors in this code. I'm not asking for it to be debugged, I would just like to know if I'm implementing the overload of operators properly.

No you can't, you are restricted to the existing ones minus a few.

Using the += would be better than your desired +++ operator

object +=2; would add 2 to the object, so simply overload the += operator