If function

So I'm trying to make a calculator that has 2 modes simple and scientific. The simple one will be only for +, -, /, *. And in this case, a request will be made to the operator to know the number of elements to use (min: 2, max: 5). I'm still working on the simple mode but I have apparently the "If" function is not really recognized in my programming... I'm still new to C++ so maybe I don't understand the function really well

here's the code

Code:

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#include <stdlib.h>
#include <stdio.h>





void viderBuffer(void);
int main()
{
    char operation;            //normal datatype intro
    float n1,n2,n3,n4,n5;
    int total;

    printf("Veuillez choisir un operateur  (+, -, *, /): \n"); //part to ask how what operator and how many operation
    scanf("%c", &operation);
    viderBuffer();
    printf("Vous voulez faire combien d'operation?\n");
    scanf("%d", &total);


    //case for 2 operation choosed
    if(total=='2')
    {
        printf("Veuillez saisir le premier chiffre: \n");
        scanf("%f", &n1);
        viderBuffer();
        printf("Veuillez taper le deuxieme chiffre: \n");
        scanf("%f", &n2);
        viderBuffer();

    /*  switch(operation)
    {
        case '+':
            printf("%.1f + %.1f = %.1f",n1, n2, n1+n2);
            break;

        case '-':
            printf("%.1f - %.1f = %.1f",n1, n2, n1-n2);
            break;

        case '*':
            printf("%.1f * %.1f = %.1f",n1, n2, n1*n2);
            break;

        case '/':
            printf("%.1f / %.1f = %.1f",n1, n2, n1/n2);
            break;

        // operator doesn't match any case constant +, -, *, /
        default:
            printf("Error! operator is not correct");
    }

*/
    }

    //case for 3 operation choosed

    else if(total=='3')
    {
        printf("Veuillez saisir le premier chiffre: \n");
        scanf("%f", &n1);
        viderBuffer();
        printf("Veuillez taper le deuxieme chiffre: \n");
        scanf("%f", &n2);
        viderBuffer();
        printf("Veuillez taper le troisieme chiffre: \n");
        scanf("%f", &n3);
        viderBuffer();
    }

    //case for 4 operation choosed

    else if(total=='4')
    {
        printf("Veuillez saisir le premier chiffre: \n");
        scanf("%f", &n1);
        printf("Veuillez taper le deuxieme chiffre: \n");
        scanf("%f", &n2);
        printf("Veuillez taper le troisieme chiffre: \n");
        scanf("%f", &n3);
        printf("Veuillez taper le quatrieme chiffre: \n");
        scanf("%f", &n4);
    }

    //case for 5 operation choosed

    else if(total=='5')
    {
        printf("Veuillez saisir le premier chiffre: \n");
        scanf("%f", &n1);
        viderBuffer();
        printf("Veuillez taper le deuxieme chiffre: \n");
        scanf("%f", &n2);
        viderBuffer();
        printf("Veuillez taper le troisieme chiffre: \n");
        scanf("%f", &n3);
        viderBuffer();
        printf("Veuillez taper le quatrieme chiffre: \n");
        scanf("%f", &n4);
        viderBuffer();
        printf("Veuillez taper le cinquieme chiffre: \n");
        scanf("%f", &n5);
        viderBuffer();
    }

    //this time I used switch case for the operation
    //right now it's only simple operation for 2 operation
    //will add another if function for the 3,4,5 operation


    return 0;
}


void viderBuffer()
{
    int c = 0;
    while (c != '\n' )  //this function is to prevent the repetition
    {
        c = getchar();
    }
}

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Code:

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if(total=='2')

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The above is wrong because total is an integer.

You likely want

Code:

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if (total == 2)

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Tim S.

This is C code. Maybe someone can move it to the right place.

oh yes I'm sorry for that I'm new to the forum site so I think I posted it in the wrong place...

Thank you so much. It is working so well now