C function "strtoull" failing

I have a code in which I am passing string "5368709120" to function strtoull() and it should had returned me number 5368709120 but instead it returns me 1073741824 which is incorrect.

What may be the possible cause of this and how to rectify it?

Code:

---

    typedef unsigned long long    ULL_Type;
    char *quotaStr = "5368709120";
    ULL_Type            quota;

    quota = strtoull(quotaStr, NULL, 10);

---

how do you print this number?

C function "strtoull" failing - The UNIX and Linux Forums

Please do not post the same question everywhere. This requires that you read about one paragraph of documentation on printf format strings. You can't print the correct value.

Works for me....

Code:

---

$ cat foo.c
#include <stdio.h>
#include <stdlib.h>

int main()
{
    typedef unsigned long long    ULL_Type;
    char *numStr = "5368709120";
    ULL_Type            num;
    num = strtoull(numStr, NULL, 10);
    printf("%s converted to numeric=%llu\n", numStr, num);

  return 0;
}
$ gcc -Wall foo.c
$ ./a.out
5368709120 converted to numeric=5368709120

---

Perhaps it's the brain damage you're using to try and print the result.
Perhaps you're not using %llu as the printf format.
Perhaps you're using code::blocks or Orwell dev-C++ on windows, in which case you need to use the platform specific formats for the 64-bit types.